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spayn [35]
3 years ago
13

How can you increase friction

Chemistry
2 answers:
Lelu [443]3 years ago
5 0

Answer:Well There is many ways to increase friction between objects. One being rubbing the two objects together quicker and harder. If there is any sort of wetness or anything related to that make sure to dry the surface between the two objects you want to create friction between so it will be more effective.

Explanation:

Luda [366]3 years ago
3 0
Rubbing stuff together
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Which of the following statements regarding spontaneous changes is false?A. Spontaneity is favored when heat is released.B. Spon
ArbitrLikvidat [17]

Answer: Option (E) is the correct answer.

Explanation:

A spontaneous reaction is defined as the process which tends to occur on its own. And, a non-spontaneous reaction is defined as a process for the completion of which we have to provide certain conditions.

For example, ice melting at 25^{o}C is spontaneous primarily due to the increase in molecular disorder (dispersal of matter). Also, melting of ice is taking place on its own without any external force.

It is not necessary that all exothermic reactions will be exothermic in nature.

Thus, we can conclude that the statement all exothermic reactions are spontaneous, is false.

4 0
3 years ago
Allena and Charissa were discussing whether Cl2 is an element or a compound. Allena said that it is an element because it has on
kobusy [5.1K]
Answer is: Allena is correct. It is an element because it is only made of chlorine atoms.
A chemical element bonded to an identical chemical element is not a chemical compound since it is made from only one element and not from two different elements. Chlorine is molecule, but not compound.
8 0
3 years ago
As noted in Assignment 1.4.1., alkylation of benzene with 1-chlorobutane in the presence of AlCl3 gives both butylbenzene and (1
Sunny_sXe [5.5K]

Answer:

Use the Bromotriflouride catalyst, BF₃

Explanation:

The BF₃ is most likely to yield less desired side products. The effect lies in the reaction mechanism.

BF₃ is a Lewis acid. Its role is to promote the ionization of the HF. This is achieved through the electrophilic mechanism. The reaction mechanism is as follows:

2 - methylpropene + H-F-BF₃ → H-F + H₃C + benzene

butylbenzene + F-BF₃ → tert-butylbenzene + H-F + BF₃ (regenerated catalyst)

6 0
3 years ago
In order for the horticulture department have its Vegetables garden it needs to increase its field's phosphorus levels. Although
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A COMPLETE FERTILISER BECAUSE OF THE PHOSPHORUS IN THE FIELD IS LIMITED. BUT DEPENDING ON THE OTHER NUTRITION IN THE SOIL. PLEASE MARK ME BRAINLIST

6 0
3 years ago
Un globo lleno de helio tenia un volumen de 8.5 L en el suelo a 20°C y a una presión de 750 torr. Cuando se le soltó, el globo s
Ray Of Light [21]

Answer:

El volumen del gas era 12.95 L

Explanation:

Se relaciona la presión y el volumen mediante la ley de Boyle, que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:  P*V=k

Por otro lado, la Ley de Charles consiste en la relación que existe entre el volumen y la temperatura absoluta de una cierta cantidad de gas ideal, el cual se mantiene a una presión constante. Esta ley dice que cuando la cantidad de gas y de presión se mantienen constantes, el cociente que existe entre el volumen y la temperatura siempre tendrán el mismo valor:  

\frac{V}{T}=k

Por último, la Ley de Gay Lussac dice que la temperatura absoluta y la presión son directamente proporcionales. Es decir, cuando se mantiene todo lo demás constante, mientras suba la temperatura de un gas subirá también su presión. Y mientras la temperatura del gas baje, lo mismo ocurrirá con la presión:

\frac{P}{T}=k

Combinado las mencionadas tres leyes se obtiene:

\frac{P*V}{T} =k

Cuando se desean estudiar dos diferentes estados, uno inicial y una final de un gas, se puede aplicar:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

Recordando que la temperatura debe usarse en grados Kelvin, conoces los siguientes datos:

  • P1: 750 torr
  • V1: 8.5 L
  • T1: 20°C= 293°K (siendo 0°C=273°K)
  • P2: 425 torr
  • V2: ?
  • T2: -20°C= 253 °K

Reemplazando:

\frac{750 torr*8.5 L}{293K} =\frac{425 torr*V2}{253 K}

Resolviendo:

V2=\frac{750 torr*8.5 L}{293K} *\frac{253 K}{425 torr}

V2= 12.95 L

<u><em>El volumen del gas era 12.95 L</em></u>

<u><em></em></u>

5 0
3 years ago
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