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3 years ago

From which layer of the atmosphere do particles of air escape into space? will give brainly

Chemistry

2 answers:

dem82 [27]3 years ago

8 0

Answer:

Exosphere

Explanation:

I took the k12 test.

svetoff [14.1K]3 years ago

4 0

Answer: The layer from where particles of air escape into space is exosphere.

Explanation:

The atmosphere is divided into layers. There are 5 main layers of atmosphere, which are: Troposphere, Stratosphere, Mesosphere, Thermosphere and Exosphere.

Troposphere is the lowest layer of the atmosphere where most of the weather occurs.
Then comes the Stratosphere which is about 50 km above the Earth's surface. It contains most of the ozone which is present in the atmosphere.
Then comes the Mesosphere which starts from 50 km and extends upto 85 km from the Earth's surface.
Then comes the Thermosphere which starts from 90 km and extends to between 500 km and 1,000 km.
Exosphere is the last layer of the atmosphere, through which anything escapes the atmosphere to space. This layer extends upto 10,000 km from the Earth's surface.

Hence, the layer from where particles of air escape into space is exosphere.

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What is due to acid formed when atmospheric and volcanic gases mix in water pizzazz helpp

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Acid rain

Explanation:

Acid rain is due to the acid formed when atmospheric and volcanic gases mix in water.

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3 years ago

In one or two sentences, explain why the combined weight of several liquids mixed in an open flask can be less than but never mo

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Answer:

Explanation:

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2 years ago

Calculate and record the expected mass of benzoic acid required to react with 20.00 ml of a 0.100 m sodium hydroxide solution. r

Marina CMI [18]

Benzoic acid reacts with sodium hydroxide based on the equation shown in the attached picture.

It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.

So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.

molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles

Therefore, number of moles of benzoic acid is also 0.002 moles
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Therefore, the required mass of benzoic acid = 0.002 x 122.12
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3 years ago

Which of the following symbols would be included in the noble gas notation for an element that had valence electrons in the 5s s

alexandr1967 [171]

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Explanation:

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2 years ago

Read 2 more answers

Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81

Gnom [1K]

Answer:

Explanation:

Given parameters;

pH = 8.74

pH = 11.38

pH = 2.81

Unknown:

concentration of hydrogen ion and hydroxyl ion for each solution = ?

Solution

The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.

It is graduated from 1 to 14

pH = -log[H₃O⁺]

pOH = -log[OH⁻]

pH + pOH = 14

Now let us solve;

pH = 8.74

since pH = -log[H₃O⁺]

8.74 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{8.74}$

[H₃O⁺] = 1.82 x 10⁻⁹mol dm³

pH + pOH = 14

pOH = 14 - 8.74

pOH = 5.26

pOH = -log[OH⁻]

5.26 = -log[OH⁻]

[OH⁻] = 10 $^{-5.26}$

[OH⁻] = 5.5 x 10⁻⁶mol dm³

2. pH = 11.38

since pH = -log[H₃O⁺]

11.38 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{11.38}$

[H₃O⁺] = 4.17 x 10⁻¹² mol dm³

pH + pOH = 14

pOH = 14 - 11.38

pOH = 2.62

pOH = -log[OH⁻]

2.62 = -log[OH⁻]

[OH⁻] = 10 $^{-2.62}$

[OH⁻] =2.4 x 10⁻³mol dm³

3. pH = 2.81

since pH = -log[H₃O⁺]

2.81 = -log[H₃O⁺]

[H₃O⁺] = 10⁻ $^{2.81}$

[H₃O⁺] = 1.55 x 10⁻³ mol dm³

pH + pOH = 14

pOH = 14 - 2.81

pOH = 11.19

pOH = -log[OH⁻]

11.19 = -log[OH⁻]

[OH⁻] = 10 $^{-11.19}$

[OH⁻] =6.46 x 10⁻¹²mol dm³

5 0

3 years ago