Answer:
C. A Spring Scale
Explanation:
Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!
Answer:
electrons (can i have brainliest)
Explanation:
Answer: A. 490.48mol
Explanation:
Using the ideal gas equation; PV =nRT
where P = Presssure = 200 atm
V = Volume = 60L
n = Number of moles
R = Gas constant = 0.08206 L.atm/mol/K
T = Temperature = 25 °C + 273 = 298K
Make "n" the subject of the formular;
n = PV / RT
= 200 x 60 / 0.08206 x 298
= 490.73 mol, which is closest to option A. 490.48mol
<h2><u>Full Question: </u></h2>
Attached in attachment.
<h2><u>Answer</u>:</h2>
Y is from Group 17. It needs 1 electron to complete its octet. There are total 6 lone pairs in molecule and 1 bond pair. The bond is covalent bond.
<h3><u>Explanation</u>:</h3>
In the picture given, we can see that it contains Lewis Dot structure of two elements X and Y. The X is said as a halogen and also correspondingly has 7 electrons in its outermost shell. The Y isn't mentioned which element it is, but similarly to X it also has 7 electrons in its outermost shell. So it is also a halogen. The group of the halogen is group 17. So Y belongs to group 17.
As the element has 7 electrons in its outermost shell, so it needs 1 electron to fulfill it's octet. It forms a covalent bond with X from where it gets 1 electron via sharing.
So now, there are three unshared electron pair of X and 3 unshared electron pair of Y. So a total of 6 unshared electron pair and 1 bond pair of electron between X and Y.