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DedPeter [7]
2 years ago
6

How many moles of brcl form when 2.74 mol cl2 react with excess br2?

Chemistry
1 answer:
egoroff_w [7]2 years ago
5 0
Following reaction arise between Br2 and Cl2

Br2   +               Cl2     →     2BrCl
(1mole)           (1mole)         (2moles)

From above balanced reaction, it can be seen that 1 mole of Br2 reacts with 1 mole of Cl2 to form 2 mole of BrCl

Thus, when <span>2.74 mol Cl2 reacts with excess Br2, 2.74 X 2 = 5.48 moles of BrCl will be formed. </span>
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Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)
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Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

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Hope that helps!

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