<span>54.8 g of MgI2 can be produced.
To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium
Atomic weight of Iodine = 126.90447
Atomic weight of Magnesium = 24.305
Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394
Now determine how many moles of Iodine and Magnesium you have
moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole
moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole
Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent.
So figure out how many moles of magnesium will be consumed by the iodine
0.393997154 mole / 2 = 0.196998577 mole.
This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2
0.196998577 mole * 278.11394 g/mole = 54.78805 g
Round the result to the correct number of significant figures.
54.78805 g = 54.8 g</span>
Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.
Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."
It means, the volume is decreased if the pressure is increased and vice versa.
Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:
Where, 
is initial pressure and 
is final pressure. Similarly, 
is initial volume and 
is final volume.
Let's plug in the values in the equation:
(537 torr)(5.30 L) = (255 torr)()
= 11.2 L
So, the new volume of the container needs to be 11.2 L.
Answer: 3.72 M
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = 
t = age of sample = 15.0 minutes
a = let initial amount of the reactant = 10.0 M
a - x = amount left after decay process = ?
The concentration of 
in a solution after 15.0 minutes have passed is 3.72 M
Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
not double replacement
it will be synthesis
they are fusing the two elements
plz mark brainliest
