Here, We know, Density = Mass / Volume
Here, mass = 44 g
volume = 40.5 ml = 40.5 cm³
Substitute their values,
d = 44 / 40.5
d = 1.086 g/cm³
In short, Your Answer would be 1.086 g/cm³
Hope this helps!
Answer:
R = 6.3456 10⁴ mile
Explanation:
For this exercise we will use Newton's second law where force is gravitational force
F = m a
The satellite is in a circular orbit therefore the acceleration is centripetal
a = v² / r
Where the distance is taken from the center of the Earth
G m M / r² = m v² / r
G M / r = v²
The speed module is constant, let's use the uniform motion relationships, with the length of the circle is
d = 2π r
v = d / t
The time for a full turn is called period (T)
Let's replace
G M / r = (2π r / T)²
r³ = G M T²²2 / 4π²
r = ∛ (G M T² / 4π²)
We have the magnitudes in several types of units
T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s
Re = 6.37 10⁶ m
Let's calculate
r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)
r = ∛ (1.027487 10²⁴)
r = 1.0847 10⁸ m
This is the distance from the center of the Earth, the distance you want the surface is
R = r - Re
R = 108.47 10⁶ - 6.37 10⁶
R = 102.1 10⁶ m
Let's reduce to miles
R = 102.1 10⁶ m (1 mile / 1609 m)
R = 6.3456 10⁴ mile
Answer:
28.7 m at 46.9°
Explanation:
The x component of the displacement is:
x = 6 m cos 0° + 25 m cos 57°
x = 19.6 m
The y component of the displacement is:
y = 6 m sin 0° + 25 m sin 57°
y = 21.0 m
The total displacement is found with Pythagorean theorem:
d = √(x² + y²)
d = 28.7 m
And the direction is found with trig:
θ = tan⁻¹(y/x)
θ = 46.9°