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4 years ago

DesCribed briefly the method you would take in location the position of an object A defined by an ordered pair of value (8,4)

Physics

1 answer:

Strike441 [17]4 years ago

3 0

Answer:

Explanation:

The method that I will use to locate the position of an object of ordered pair of value (8, 4) is known as the graphical method. The ordered pair of value (8, 4) is known as the coordinates. In graphical method, the coordinate will be located on the Cartesian plane having both x and y axis. The graph will be a 2-dimensional graph with y-axis being along the vertical and the x-axis along the horizontal.

The coordinates (8, 4) means that the value of x is +8 and the value of y is +4. To locate the point P(8, 4) on the graph, we will have to locate both points on the positive x and y axis respectively and then mark out their point of intersection. This point of intersection will be the position of the object defined as ordered pair of value (8,4).

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If an atom has a mass number of 23, which of the following is always true?

WINSTONCH [101]

The number of protons in the nucleus does not equal the number of nuetrons

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3 years ago

supposed the Kingfisher Dives with an average speed of 4.6 m / s for 1.4 seconds before hitting the water. What is the height fr

timama [110]

Answer:

h = 1.07 m

Explanation:

It is given that,

The average sped of the kingfisher, v = 4.6 m/s

Time, t = 1.4 s

Final speed, v = 0 (as it hits the water)

We need to find the height from which the bird dove. Let the height is h. According to the conservation of energy.

$mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(4.6)^2}{2\times 9.8}\\\\h=1.07\ m$

So, the bird dove from a height of 1.07 m.

3 0

4 years ago

A wave on a string has a wavelength of 0.90 m at a frequency of 600 Hz. If a new wave at a frequency of 300 Hz is established in

kobusy [5.1K]

Answer:

λ₂ = 1.8 m

Explanation:

given,

wavelength of the string 1 = 0.90 m

frequency of the string 1 = 600 Hz

wavelength of string 2 = ?

frequency of the string 2 = 300 Hz

we now,

$f\ \alpha\ \dfrac{1}{\lambda}$

now,

$\dfrac{f_1}{f_2}=\dfrac{\lambda_2}{\lambda_1}$

$\dfrac{600}{300}=\dfrac{\lambda_2}{0.9}$

λ₂ = 2 x 0.9

λ₂ = 1.8 m

Hence, the wavelength of the second string is equal to λ₂ = 1.8 m

8 0

3 years ago

What is the maximum centripetal acceleration experienced by a person standing still on the surface of the Earth? Where must they

skelet666 [1.2K]

Answer:

The person must be located in the Equator Line. The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.

Explanation:

Physically speaking, the centripetal acceleration ( $a_{r}$ ), measured in meters per square second, experienced by a person is defined by the following expression:

$a_{r} = \omega^{2}\cdot r$ (1)

Where:

$\omega$ - Angular speed of the Earth, measured in radians per second.

$r$ - Distance perpendicular to the rotation axis, measured in meters.

Since rotation axis passes through poles and distance described above is directly proportional to centripetal acceleration. The person must be located in the Equator Line, which is equivalent to the radius of the planet.

In addition, the angular speed of the Earth can be calculated in terms of its period ( $T$ ), measured in seconds: