Is this a complete question or is there a problem to match it? maybe goggle it?
Answer:
"0.049 W" is the correct answer.
Explanation:
According to the given question,
As we know,
⇒ 
Now,
⇒ 
or,
Answer:
x(t) = ⅟₁₀₈t⁴ + 10t + 24
v(t) = ⅟₂₇t³ + 10
Explanation:
a(t) = C₁t²
velocity is the integral of acceleration
v(t) = ⅓C₁t³ + C₂
position is the integral of velocity
x(t) = (⅟₁₂C₁)t⁴ + C₂t + C₃
x(0) = 24 = (⅟₁₂C₁)0⁴ + C₂0 + C₃
C₃ = 24
x(6) = 96 = (⅟₁₂C₁)6⁴ + C₂6 + 24
72 = 108C₁ + 6C₂
C₂ = 12 - 18C₁
v(6) = 18 = ⅓C₁6³ + C₂
18 = 72C₁ + C₂
18 = 72C₁ + (12 - 18C₁)
6 = 54C₁
C₁ = 1/9
C₂ = 12 - 18(1/9)
C₂ = 10
Potential energy = m · g · h
-- When you held the ball at 2.0 meters above the floor, it had
(0.5 kg) · (9.8 m/s²) · (2.0 m) = 9.8 Joules of potential energy.
-- After it bounced and went back up as high as it could, it was only 1.8 meters above the floor. Its potential energy was
(0.5 kg) · (9.8 m/s²) · (1.8 m) = 8.82 Joules
-- Between the drop and the top of the bounce, it lost
(9.8 - 8.82) = <em>0.98 Joule</em> .
-- The energy was lost when the ball hit the floor. During the hit, 0.98 joule of kinetic energy turned to <em>thermal energy</em>, which slightly heated the ball and the floor.
