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3 years ago

Centrifugal force increases with

2 answers:

8 0

Centrifugal force is not a real force.

When you move around a curve, there IS a real force pulling you
around the curve. Since your body wants to go straight, it feels as if
there's a force trying to pull you away from the curve. But there isn't.

That feeling of a force is greater when your speed around the curve
is greater, or when the curve is tighter, i.e. smaller radius.

Slav-nsk [51]3 years ago

5 0

Centrifugal force is said to be the outward force being experienced by an object/objects travelling in a circular path. The force is directly affected or depends on the mass of the object, its rotational speed and the object's distance from the center. An object that is bigger, has a greater speed compared to others, and has a greater distance from the center is said to display a greater force. This means to say that centrifugal force increases with the size of the object, its speed when rotating and distance from the center. The bigger the object, the faster the speed and the farther from the center is equal to a greater centrifugal force.

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Suppose the voltage source for a series RL-circuit were given as V0sin(ωt) instead of V0cos(ωt). Write an expression for the cur

Gala2k [10]

Answer:

Explanation:

This is an RL circuit, therefore:

Impedance; z = $\mathbf{\sqrt{R^2+L^2}}$

$\mathbf{z = \sqrt{R^2+(Lw)^2}}$

Current amplitude

$\mathbf{I_o = \dfrac{V_o}{z}} \\ \\ \mathbf{I_o = \dfrac{V_o}{\sqrt{R^2+L^2\omega ^2}}}$

Given that:

$V_o = 1.9 \ V \\ \\ \omega= 51 \ rad/s\\\\ R = 21 \Omega \\ \\ L = 0.52 H$

∴

$I_o= \dfrac{1.9}{\sqrt{21^2+(0.52\times 51)^2}}$

$\mathbf{I_o= 0.0562} \\ \\ \mathbf{I_o = 56.2 \ mA}$

Phase constant :

$tan \ \phi = \dfrac{L \omega}{R } \\ \\ tan \ \phi = \dfrac{0.52 \times 51}{21} \\ \\ tan \phi = 1.263$

$\text{Phase constant : }\phi = tan^{-1} (1.263) \\ \\ \phi = 51.6^0\\ \\\text{To radians} \phi = 51.6 \times \dfrac{\pi}{180} \\ \\ \phi = 0.287 \pi \\ \\ \mathbf{\phi = 0.9 \ rad}$

3 0

3 years ago

What is measurement

larisa86 [58]

Answer:

the size, length, or amount of something, as established by measuring.

Explanation:

3 0

3 years ago

Technician A says that gears may be used to apply torque to other rotating parts. Technician B says that gears may be used to mu

Goryan [66]

Answer:

Both technicians are right.

Explanation:

Torque is defined as a rotational force that can be calculated by the formula T= F.d. Being F the force applied to a body to make it rotate and d the distance since the force is applied.

$T= F . d$

So technician A is saying that gear can apply a torque to another gear, and that is true because it’s applying a rotational force to the gear next to it, in simple terms -anytime I make something rotate, I'm generating a torque-. And for technician B, the torque also can vary as a function of the distance of the force applied (size of the gear), so, it can multiply the torque and change the rotation speed.

5 0

4 years ago

TRUE OR FALSE. if an object does not change its position at a given time interval, then it is at rest or its speed is zero or no

Andrew [12]

Answer:

true

Explanation:

a body can only be accelerating and have speed if it's in motion

3 0

3 years ago

3. The largest asteroid in the solar system is 1 Ceres. It has a mass of 9.3835

Ira Lisetskai [31]

Answer:

2.8351×10^7 N/kg

Explanation:

We know that,

W = mg -------(1)

where W = weight, m = mass, g = gravitational acceleration

Also from Newton's law of gravitation we know that,

F = GMm/r²

Where,

F = gravitational force,

G = universal gravitational constant

M,m = masses of object under gravitational influence

r = distance between the two center of masses.

Here we get

F = (Gm/r²)M -------(2)

From 1 and 2

The acceleration due to gravity = gravitational field intensity

So if you consider the gravitational field intensity at the surface of the asteroid,it is equal to the acceleration due to gravity at the same place.

So we get,

g = (6.67×10^-11)×9.3835×10^20/(47²) = 2.8351×10^7 N/kg

3 0

4 years ago