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Assoli18 [71]
3 years ago
11

Which career professionals are part of the Architecture and Construction career cluster? Check all that apply.

Physics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

A,B,D,E,F

Explanation:

I took the test for yall.

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A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Eart
Charra [1.4K]
11,000 m = 11 km

11 km/s over 380,000km

380,000 / 11 = 34545.4 seconds

34545.4 / 60 = 575.7 minutes
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3 years ago
A distant galaxy has a redshift z = 5.82 and a recessional velocity vr = 287,000 km/s (about 96% of the speed of light.) Notice
vlabodo [156]

Answer: 4100 Mpc

Explanation:

Since H o = 70 km/s/Mpc

Redshift z = 5.82

Recessional velocity vr = 287,000 km/s

Then, the distance to the galaxy in light years will be:

= Recessional velocity / H o

= 287000 / 70

= 4100 Mpc

7 0
3 years ago
Nighttime is the result of
Fynjy0 [20]

Explanation:

Answer- D(Earth's spin)

3 0
3 years ago
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What type of energy is the sum of an object’s potential and kinetic energy?
nikklg [1K]

Answer: its mechanical energy

Explanation:

8 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
4 0
3 years ago
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