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suter [353]
3 years ago
15

The angle a vector makes with the x-axis of a coordinate system must be what size in order to make one or more of its components

negative?
A)less than 30 degrees
B)between 30 and 60 degrees
C)between 61 and 90 degrees
D)greater than 90 degrees
Physics
2 answers:
lesya [120]3 years ago
5 0
D)greater than 90 degrees
Aneli [31]3 years ago
3 0
If only 1 option is correct then it is (D)
All the others can also make one component negative, all depends how u measured the angle.
all the best
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When you ask for "joules per second", you're asking for "watts".
The rate of energy "transfer" is 'power'.  In this case, the light bulb
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Electrical power = (voltage) x (current) =

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What is he total resistance?<br> A. 20 ohms<br> B. 90 ohms<br> C. 40 ohms<br> D. 30 ohms
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An old-fashioned LP record rotates at 33 1/3 RPM
Ksenya-84 [330]

Answer:

Part a) \frac{5}{9}\ \frac{rev}{sec}

Part b) \frac{9}{5}\ \frac{sec}{rev}

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

33\frac{1}{3}\ \frac{rev}{min}

Convert mixed number to an improper fraction

33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}

Remember that

1\ min=60\ sec

Convert rev/min to rev/sec

\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}

Simplify

\frac{5}{9}\ \frac{rev}{sec}

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

\frac{9}{5}\ \frac{sec}{rev}

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If you apply 120 newtons to the machine's input, the output force is

                 (2.5 x 120 newtons)  =  300 newtons.

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