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dimulka [17.4K]
3 years ago
15

What do microwaves and x-rays have in common? They are visible. They are mechanical waves that require a medium. They are part o

f the electromagnetic spectrum. They carry sound.
Physics
2 answers:
jolli1 [7]3 years ago
6 0

Answer:

They are part of the electromagnetic spectrum

Explanation:

The electromagnetic spectrum consists of the following:

Gamma Rays            HIGH FREQUENCY, SHORT WAVELENGTH

<em>X-Rays</em>

Ultraviolet Rays

Visible Light

Infrared Rays

<em>Microwaves</em>

Radio Waves               LOW FREQUENCY, LONG WAVELENGTH

dalvyx [7]3 years ago
5 0

Answer:

C

Explanation:

Took test

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When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.

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You can calculate acceleration with the following equation: Acceleration = (final velocity - starting velocity) ÷ time it takes
Whitepunk [10]

Answer:

1000m/s²

Explanation:

Given parameters:

Initial velocity  = 6000m/s

Final velocity  = 11000m/s

Time  = 50s

Unknown:

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Solution:

Acceleration is the rate of change of velocity with time:

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Therefore;

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7 0
3 years ago
Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f
Alex17521 [72]

Answer:

g' = g/4

Explanation:

  • The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
  • This force can be expressed according  the Newton's Universal Law of Gravitation , as follows:

       F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} }  (1)

  • From Newton's 2nd Law, we have:
  • F = m* a (2)
  • Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
  • Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

       g = G*\frac{m_{E} }{r_{E}^{2} }  (3)

  • Since G is an universal constant, and the mass mE remains constant, if we double the radius of  the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

        g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} }  = g*\frac{1}{4}  =\frac{g}{4} (4)

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