I don’t worry wewwwww it is a good time to get it done lol lol i don’t worry about it lol lol i lol
Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
Answer:
<h2>Electric charge</h2>
Explanation:
The rate of the flow of electric charge is known as electric current. <u>By convention, the direction of electric current is always the direction of net flow of positive charge.</u>
Answer:
<em>The correct option is 1. 720 m</em>
Explanation:
<u>Projectile Motion</u>
When an object is launched in free air (no friction) with an initial speed vo at an angle 
, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.
The initial velocity has these components in the x and y coordinates respectively:
And we know the plane has an altitude of 600 m, so the package will reach ground level when:
The vertical distance traveled is given by:
We'll set up an equation to find the time when the package lands
Solving for t, we find only one positive solution:
The horizontal distance is:
The correct option is 1. 720 m
