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Allisa [31]
4 years ago
11

We have seen that starlight passing through the interstellar medium is dimmed and reddened. Look at the photo of a sunset on Ear

th. The Sun’s light also appears reddish at sunset. Given your understanding of the reddening of starlight, why do you think sunsets appear red?
Physics
1 answer:
vovikov84 [41]4 years ago
7 0

Answer:

Explanation:

Reddening of sun's rays at sunset and sunrise is due to scattering of light . The white light consisting of seven colours coming from the sun are scattered in different directions when they fall on the air particles present in atmosphere . Red coloured light scatters least and it travels straight forward to the viewer on the earth . On the other hand other colours scatter most and therefore they go out of area of vision for the viewer on the earth . Since only red colour reaches the eye of the viewer , sun's ray appear red . This happens during sunrise and sunset . It is so because during this period , sun rays travel far greater distance through  atmosphere , so scattering is most pronounced .

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Letter C on the map labels which feature of the Middle East?
likoan [24]

Honest, the map is so tiny, and so fuzzy when I blow it up, I really can't see anything on it clearly.  But I think maybe I do see a letter ' C ' in the eastern Mediterranean, with a curved line over to the southern Gaza strip, where it meets Sinai.  So I'll say it's the Gaza Strip.

6 0
3 years ago
Two identical conducting spheres A and B carry equal charge. They are separated by a distance much larger than their diameters.
VashaNatasha [74]
What a delightful little problem !
Here's how I see it:

When 'C' is touched to 'A', charge flows to 'C' until the two of them are equally charged.  So now, 'A' has half of its original charge, and 'C' has the other half.

Then, when 'C' is touched to 'B', charge flows to it until the two of <u>them</u> are equally charged.  How much is that ?  Well, just before they touch, 'C' has half of an original charge, and 'B' has a full one, so 1/4 of an original charge flows from 'B' to 'C', and then each of them has 3/4 of an original charge.

To review what we have now:  'A' has 1/2 of its original charge, and 'B' has 3/4 of it.

The force between any two charges is:

F = (a constant) x (one charge) x (the other one) / (the distance between them)².

For 'A' and 'B', the distance doesn't change, so we can leave that out of our formula.

The original force between them was  3 = (some constant) x (1 charge) x (1 charge).

The new force between them is  F = (the same constant) x (1/2) x (3/4) .

Divide the first equation by the second one, and you have a proportion:

3 / F  =  1 / ( 1/2 x 3/4 )

Cross-multiply this proportion:

3 (1/2 x 3/4)  = F

F  =  3/2 x 3/4  =  9/8  =  <em>1.125 newton</em>.


That's my story, and I'm sticking to it.
 
5 0
3 years ago
The process of recording the strength of the contraction of a muscle when it is stimulated by an electrical current is known
Naddik [55]
i dont know the answer of your question correctly

3 0
4 years ago
Many people confuse the terms energy, work, and power. Explain how they are alike and how they are different
nikitadnepr [17]
Work, is the speed at which energy transfers.
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3 0
3 years ago
A 350 gram mass is tied to a string and spin in a horizontal circle with a radius of 11.0cm.The speed of the mass is held consta
SSSSS [86.1K]

Explanation:

a) The angular speed omega is given defined as

omega = #rev/period = 1 rev/(0.6 s) = 1.7 rev/s

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b) v = (omega)×r

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= 1.16 m/s

7 0
3 years ago
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