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Svetach [21]
3 years ago
9

If an element has the atomic number of 117 how many protons will it have and how many electrons will it have

Chemistry
1 answer:
Xelga [282]3 years ago
5 0
The # of protons is the same as the atomic number.

Protons: 117
Electrons: You need to know the atomic mass to find this. Use:
                   Atomic mass - atomic number = # electrons
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Illusion [34]
I believe it would weigh less if it’s blown up with helium because helium is lighter than air
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Please help asap
Helen [10]
C. carbon
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4 0
3 years ago
How many atoms are found in the products of the following chemical equation?
coldgirl [10]

There are 13 atoms in the product

<h3>Further explanation</h3>

Given

Reaction

H2SO4 + 2KOH --> K2SO4 + 2H2O

Required

The number of atoms

Solution

In a chemical equation, there are reactants on the left and products on the right

Reactants : H2SO4 + 2KOH

Products : K2SO4 + 2H2O

The number of atoms is determined by their reaction coefficient and the subscript of the atoms in the compound

K2SO4 (coefficient = 1) :

K = 2 atoms

S = 1 atom

O = 4 atoms

Total atoms = 7 atoms

2H2O(coefficient = 2) :

H = 2 x 2 = 4 atoms

O = 2 x 1 = 2 atoms

Total atoms = 6 atoms

Total = 13 atoms

5 0
3 years ago
1 Ammonia, NH3, reacts with incredibly strong bases to produce the amide ion, NH2 -. Ammonia can also react with acids to produc
Charra [1.4K]

Answer:

a) ammonium ion

b) amide ion

Explanation:

The order of decreasing bond angles of the three nitrogen species; ammonium ion, ammonia and amide ion is NH4+ >NH3> NH2-. Next we need to rationalize this order of decreasing bond angles from the valence shell electron pair repulsion (VSEPR) theory perspective.

First we must realize that all three nitrogen species contain a central sp3 hybridized carbon atom. This means that a tetrahedral geometry is ideally expected. Recall that the presence of lone pairs distorts molecular structures from the expected geometry based on VSEPR theory.

The amide ion contains two lone pairs of electrons. Remember that the presence of lone pairs causes greater repulsion than bond pairs on the outermost shell of the central atom. Hence, the amide ion has the least H-N-H bond angle of about 105°.

The ammonia molecule contains one lone pair, the repulsion caused by one lone pair is definitely bless than that caused by two lone pairs of electrons hence the bond angle of the H-N-H bond in ammonia is 107°.

The ammonium ion contains four bond pairs and no lone pair of electrons on the outermost nitrogen atom. Hence we expect a perfect tetrahedron with bond angle of 109°.

5 0
3 years ago
Information related to a titration experiment is given in the balanced equation and table below.
Scorpion4ik [409]

Answer:

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

6 0
3 years ago
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