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liberstina [14]
3 years ago
13

What is the chemical symbol of an element

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

A chemical symbol is a shorthand method of representing an element. Instead of writing out the name of an element, we represent an element name with one or two letters. As you know, the periodic table is a chemist's easy reference guide. ... Each element is represented by a chemical symbol consisting of letters

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What is a nuclear acid ​
Ronch [10]

Answer:

Nucleic acid is an important class of macromolecules found in all cells and viruses. Deoxyribonucleic acid (DNA) encodes the information the cell needs to make proteins.

A related type of nucleic acid, called ribonucleic acid (RNA), comes in different molecular forms that participate in protein synthesis.

8 0
3 years ago
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What is the pressure in a 24.0-LL cylinder filled with 32.7 gg of oxygen gas at a temperature of 319 KK? Express your answer to
Blizzard [7]

Answer:

The pressure in that cylinder = 1.12atm

Explanation:

We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus

P = nRT/V

Where n = number of moles

R = the gas constant

T is the Temperature, V is the volume and P is the pressure.

Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol

The first step is to find n using

n = mass of O2/molar mass of O2

=32.7/32

=1.0219

Now, using P =nRT/V

P = 1.0219 ×0.0821×319÷24

Therefore P = 1.12atm

8 0
3 years ago
Use the given figure to complete the statement below.
MakcuM [25]

Easy, its vertical :3


4 0
3 years ago
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Is " Energy created " an Endothermic reaction or an Exothermic reaction?
podryga [215]
A endothermic reaction
6 0
3 years ago
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

          2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)

And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

   P_{H_{2}} = 3 \times P_{N_{2}} = 0.69 atm

Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

                        = 0.23 aatm

So, P_{NH_{3}} = 2.3 - 2(0.23)

                       = 1.84 atm

Now, expression for K_{p} will be as follows.

         K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}

           K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}

                      = \frac{0.23 \times 0.33}{3.39}

                     = 0.0224

or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

6 0
3 years ago
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