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Ganezh [65]
3 years ago
10

This particle determines what element you have - the element's identity.

Chemistry
1 answer:
scoundrel [369]3 years ago
4 0

Answer:

protons

These particles do not vary in quality from one element to another; rather, what gives an element its distinctive identification is the quantity of its protons, called its atomic number. Protons and neutrons contribute nearly all of an atom's mass; the number of protons and neutrons is an element's mass number

Explanation:

You might be interested in
Calculate the density of sulfuric acid if 35.4 ml of the acid has a mass of 65.14 grams. (Please show how you got this answer)
vesna_86 [32]

Answer:

d = 1.85 g/cm³

Explanation:

Given data:

Volume of sulfuric acid = 35.4 mL

Mass of sulfuric acid = 65.14 g

Density of sulfuric acid = ?

Solution:

1 ml = 1cm³

Formula:

d = m/v

d = 65.14 g / 35.2 cm³

d = 1.85 g/cm³

7 0
3 years ago
Different enzymes that catalyze the same reaction are known as _____.
maw [93]

Answer:

<em><u>Isozymes</u></em>

Explanation:

Isozymes are enzymes that differ in amino acid sequence but catalyze the same chemical reaction. These enzymes usually display different kinetic parameters, or different regulatory properties.

7 0
3 years ago
What is the relationship between metals and the number of electrons in the outer level?
gayaneshka [121]
Elements in group 1-2, 13-18, the number of valence electrons is related to the group number. For example, in the first group, the alkali metals there is one valence electron, however in group 13, there are 3 valence electrons. Valence electrons are also known as the outershell electrons.
4 0
3 years ago
29.0 argon combine completely with 4.30 g of Sulfur.
Iteru [2.4K]

Answer:

33.3

Explanation:

if we were to add 29.0 of argon and 4.30 of sulfur and that would come out 33.3.

8 0
3 years ago
How many liters of Cl2 gas will you have if you are using 63 g of Na?
ELEN [110]

Answer:

You will have 19.9L of Cl2

Explanation:

We can solve this question using:

PV = nRT; V = nRT/P

<em>Where V is the volume of the gas</em>

<em>n the moles of Cl2</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is 273.15K assuming STP conditions</em>

<em>P is 1atm at STP</em>

The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:

63g * (1mol / 70.906g) = 0.8885 moles

Replacing:

V = 0.8885mol*0.082atmL/molK*273.15K/1atm

V = You will have 19.9L of Cl2

6 0
3 years ago
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