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3 years ago

What is the mass of 5.50 mol of pure liquid bromine ?

Chemistry

1 answer:

GREYUIT [131]3 years ago

5 0

Answer:

m Br = 439.472 g

Explanation:

mass Br = ?

∴ mol Br = 5.50 mol

∴ molar mass Br 79.904 g/mol

mass = (mol)*(g/mol)

⇒ m Br = (5.50 mol)*(79.904 g/mol)

⇒ m Br = 439.472 g

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. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the

Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

$\frac{P}{T}=k$

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

P1= 0.450 atm
T1= 20 C= 293.15 K (being 0 C= 273.15 K)
P2=0.750 atm
T2= ?

Replacing:

$\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}$

Solving:

$T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }$

$T2=\frac{0.750 atm}{0.450 atm} *293.15K$

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

The final temperature of sulfur dioxide gas is 215.43 C

6 0

3 years ago

How much heat is required to increase the temperature of 35.0 grams of water from 10.0°C to 45.0°C? (The specific heat of water

kati45 [8]

Q = mCΔT
Q is heat in Joules, m is mass, C is the specific heat of water, delta T is the change in temperature

Q = (35g)(4.18)(35 degrees) = 5121 Joules or 5.12 kJ required

7 0

2 years ago

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15. If the moon is 384,400km away. Does it take more than a second for light to travel from the Earth to the moon?

marishachu [46]

Answer:

Yes

Explanation:

The speed of light is about 300 000 km per second, so light takes about 1.28 seconds to travel from the Moon to the Earth.

3 0

1 year ago

31.5 grams of an unknown substance is heated to 102.4 degrees Celsius and then placed into a calorimeter containing 103.5 grams

Alexxandr [17]

Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

Heat gained = Heat lost
mC(T2-T1) = - mC(T2-T1)
31.5C (102.4 - 32.5) = 103.5(4.18)(32.5 - 24.5)
C = 1.57 J/C-g

Hope this helps.

5 0

2 years ago

Cellular respiration involves the use of oxygencarbon dioxide and the release of carbon dioxideoxygen

Reil [10]

Cellular respiration can be thought of as the opposite of photosynthesis. In cellular respiration oxygen is turned into carbon dioxide while in photosynthesis carbon dioxide is tuned to oxygen.

I hope this helps. let me know in the comments if anything is unclear.

3 0

2 years ago

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