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3 years ago

Pb(NO3)2(aq) + KCl(aq) ---- → KNO3(aq) + PbC12(s)

1 answer:

6 0

If you’re asking to balance the equation then:

Pb(NO3)2(aq) + 2KCl(aq) -> 2KNO3(aq) + PbCl2(s)

Just remember: the equations at the end is Cl not C12

Note: the small number on the bottom (subscripts) apply to the one element if it’s inside the bracket and if the small number is on the outside of the bracket it applies to all the elements. For example the 3 in (NO3)2 applied only to the O (oxygen) and the 2 applies to both N and O but don’t forget it’s multiplied. So it would be 2 N’s and 6 O’s bc the 3 multiplies with the 2 only for the O.

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Ice floats on the surface of water because ice is less dense than liquid water <br> true or false?

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Answer:

yes it is true.

Ice floats on the surface of water because ice is less dense than liquid water

Explanation:

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3 years ago

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At what point does the radiation start to affect satellites in the atmosphere

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After that have been up for a while thay are metal

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3 years ago

Fill in the blanks for the following statements: The rms speed of the molecules in a sample of H2 gas at 300 K will be _________

Anna007 [38]

Answer : The rms speed of the molecules in a sample of $H_2$ gas at 300 K will be four times larger than the rms speed of $O_2$ molecules at the same temperature, and the ratio $\mu _{rms}(H_2)/\mu _{rms}(O_2)$ constant with increasing temperature.

Explanation :

Formula used for root mean square speed :

$\mu _{rms}=\sqrt{\frac{3RT}{M}}$

where,

$\mu _{rms}$ = rms speed of the molecule

R = gas constant

T = temperature

M = molar mass of the gas

At constant temperature, the formula becomes,

$\mu _{rms}=\sqrt{\frac{1}{M}}$

And the formula for two gases will be,

$\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}$

Molar mass of $O_2$ = 32 g/mole

Molar mass of $H_2$ = 2 g/mole

Now put all the given values in the above formula, we get

$\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4$

Therefore, the rms speed of the molecules in a sample of $H_2$ gas at 300 K will be four times larger than the rms speed of $O_2$ molecules at the same temperature.

And the ratio $\mu _{rms}(H_2)/\mu _{rms}(O_2)$ constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.

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3 years ago

If two gases A and B are at the same temperature and pressure, the ratio of their effusion rates is

Fed [463]

If the gases are at the same temperature and pressure, the ratio of their effusion rates is directly proportional to the ratio of the square roots of their molar masses:

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

Where

R₁ and R₂ are the rates of the two gas
M₁ and M₂ are the molar masses of the two gas

From the Graham's law equation, we can see that the ratio of the rates of effusion of the two gases is directly proportional to the square root of their molar masses

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

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2 years ago

Why is measuring heat so important

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Answer:

to see what will work with that temp

Explanation:

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3 years ago