Question

2koh+bacl2>2kcl+Ba(OH)2 what is the net ionic.I know all hydroxides are insolubles except with group 1A ,I presumed Ba(Oh)2 is aqueous.so I cant come up with a net ionic equation.

Answer 1

Answer:

$\boxed{\text{No reaction}}$

Explanation:

1. "Molecular" equation

$\rm 2KOH+ BaCl _{2} \longrightarrow \, 2KCl + Ba(OH) _{2}$

Solubility rules

1. Salts containing Group 1 elements are soluble.
2. Salts containing halides are generally soluble, except the halides of silver, mercury(I), and lead.
3. All metallic hydroxides are insoluble except Group 2 from calcium down. So, BaCl₂ is soluble, and the molecular equation is

$\rm 2KOH(aq)+ BaCl _{2} (aq) \longrightarrow \, 2KCl(aq) + Ba(OH) _{2} (aq)$

2. Ionic equation

$\rm 2K ^{+} (aq) + 2OH ^{-} (aq)+ Ba ^{2+} (aq) + 2Cl ^{-} (aq) \longrightarrow \, 2K ^{+} (aq)+ 2Cl ^{-} (aq) + Ba ^{2+} (aq) + 2OH ^{-} (aq)$

3. Net ionic equation

$\rm 2K ^{+} (aq) + 2OH ^{-} (aq)+ Ba ^{2+} (aq) + 2Cl ^{-} (aq) \longrightarrow \, 2K ^{+} (aq)+ 2Cl ^{-} (aq) + Ba ^{2+} (aq) + 2OH ^{-} (aq)$

Cancel all ions that appear on both sides of the reaction arrow (in boldface).

$\textbf{2K ^{+} (aq) + 2OH ^{-} (aq) + Ba ^{2+} (aq) + 2Cl ^{-} (aq)}\\\longrightarrow \,\textbf{2K ^{+} (aq)+ 2Cl ^{-} (aq) + Ba ^{2+} (aq) + 2OH ^{-} (aq)}\\\text{Everything cancels. There is no net ionic equation.}\\\text{(nothing)} \longrightarrow \, \text{(nothing)}\\\text{Answer: }\boxed{\textbf{No reaction}}$