A. The Dawes limit tells
us that the resolving power is equal to 11.6 / d, where d is the diameter of
the eye’s pupil in units of centimeters. The eye's pupil can dialate to approximately
7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc
minute ~ 17 arc seconds<span>
Although, the standard answer for what people can really see
is about 1 arc minute.
</span>
<span>
B. It is considered as linear, so given a 10 meter telescope
(10,000 mm): </span>
10000 / 7 = 1428 times
better for the 10 meter scope ~ 1400 times better (in 2 significant figures)
<span>
<span>C. For a 7 cm interferometer, that is just similar to a 7 cm
scope. Therefore we would expect </span></span>
<span><span>11.6 / 7 = 1.65 arc seconds ~ 1.7 arc seconds</span></span>
<span><span>T</span></span>his value is what
we typically can get from a 7 cm scope.
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:
P = ρgh
This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:
P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
300
Explanation:
100 x 3 =300 simple and easy
Mass= volume x density
Mass= 90kg/m^3 x 2.3m^3
Therefore, Mass= 207 kg
I believe it is lithosphere
