Question

Consider the reaction. mc033-1.jpg At equilibrium, the concentrations are as follows. [NOCl] = 1.4 ´ 10–2 M [NO] = 1.2 ´ 10–3 M [Cl2] = 2.2 ´ 10–3 M What is the value of Keq for the reaction expressed in scientific notation? 1.6 ´ 10–5 6.2 ´ 10–4 6.2 ´ 104 1.6 ´ 105

Answer 1

Answer is:value of Keq for the reaction is 1,6·10⁻⁵.
Chemical reaction: 2NOCI(g) ⇄ 2NO(g) + CI₂(g).
[NOCl] = 1,4·10⁻² M.
[NO] = 1,2·10⁻³ M.
[Cl₂] = 2,2·10⁻³ M.
K = [NO]² · [Cl₂] ÷ [NOCl]².
K = (1,2·10⁻³ M)² · 2,2·10⁻³ M ÷ (1,4·10⁻² M)².
K = 1,6·10⁻⁵.

Answer 2

Answer: $1.6\times 10^{-5}$

Explanation: Equilibrium constant is the ratio of product of concentration of products to the product of concentration of reactants each term raised to their stochiometric coefficients.

$2NOCI(g)\rightleftharpoons 2NO(g) +CI_2(g).$

Given :

$[NOCl]=1.4\times 10^{-2}M$.

$[NO]=1.2\times 10^{-3}M$.

$[Cl_2]=2.2\times 10^{-3}M$.

$K=\frac{[NO]^2[Cl_2]}{[NOCl]^2}$

$K=\frac{[1.4\times 10^{-2}]^2[1.2\times 10^{-3}]}{[2.2\times 10^{-3}]^2}$

$K=1.6\times 10^{-5}$