Answer:
Secondary voltage on second transformer is 200 volt.
Explanation:
It is given two transformer
Let us consider first transformer.
Number of turns in primary 
Numb er of turns in secondary 
Now consider second transformer
Number of turns in primary 
Number of turns in secondary 
Now it is given that same voltage of 50 volt is applied to primary of both the transformer.
For second transformer



So secondary voltage on second transformer is 200 volt
There are mistakes in the question.The correct question is here
A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntable’s angular velocity, in rpm, just after this event?
Answer:
w=50 rpm
Explanation:
Given data
The mass turntable M=2kg
Diameter of the turntable d=20 cm=0.2 m
Angular velocity ω=100 rpm= 100×(2π/60) =10.47 rad/s
Two blocks Mass m=500 g=0.5 kg
To find
Turntable angular velocity
Solution
We can find the angular velocity of the turntable as follow
Lets consider turntable to be disk shape and the blocks to be small as compared to turntable

where I is moment of inertia

Answer:
The carrier lengthen is 0.08436 m.
Explanation:
Given that,
Length = 370 m
Initial temperature = 2.0°C
Final temperature = 21°C
We need to calculate the change temperature
Using formula of change of temperature



We need to calculate the carrier lengthen
Using formula of length

Put the value into the formula


Hence, The carrier lengthen is 0.08436 m.
Answer:
Their velocity after the impact is 20.85 m/s.
Explanation:
Given that,
Mass of falcon, 
Mass of dove, 
Initial speed of the falcon, 
Initial speed of the dove, 
We need to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :

So, their velocity after the impact is 20.85 m/s.
<span>when it returns to its original level after encountering air resistance, its kinetic energy is
decreased.
In fact, part of the energy has been dissipated due to the air resistance.
The mechanical energy of the ball as it starts the motion is:
</span>

<span>where K is the kinetic energy, and where there is no potential energy since we use the initial height of the ball as reference level.
If there is no air resistance, this total energy is conserved, therefore when the ball returns to its original height, the kinetic energy will still be 100 J. However, because of the presence of the air resistance, the total mechanical energy is not conserved, and part of the total energy of the ball has been dissipated through the air. Therefore, when the ball returns to its original level, the kinetic energy will be less than 100 J.</span>