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serious [3.7K]
3 years ago
6

The cells lie odjacent to the sieve tubes​

Physics
1 answer:
nignag [31]3 years ago
4 0

Answer:

<h2><em>Almost</em><em> </em><em>always</em><em> </em><em>adjacent</em><em> </em><em>to</em><em> </em><em>nucleus</em><em> </em><em>containing</em><em> </em><em>companion</em><em> </em><em>cells</em><em>,</em><em> </em><em>which</em><em> </em><em>have</em><em> </em><em>been</em><em> </em><em>produced</em><em> </em><em>as</em><em> </em><em>sister</em><em> </em><em>cells</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>sieve</em><em> </em><em>elements</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>mother</em><em> </em><em>cell</em><em>.</em><em> </em></h2>
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A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta
My name is Ann [436]

Answer:

a).K=528.92 \frac{N}{m}

b).m=4.84kg

Explanation:

a).

The work of the spring is find by the formula:

w_s =\frac{1}{2}*k*x^2

So knowing the work can find the constant K'

3.2J =\frac{1}{2}*k*(0.11m)^2

Solve for K'

K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}

K=528.92 \frac{N}{m}

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

F=m*a

m=\frac{F}{a}=\frac{K*x}{a}

m=\frac{528.9*0.11m}{12m/s^2}

m=4.84kg

8 0
3 years ago
In stars mor massive than the sun, fusion continues until the core is almost all....
serious [3.7K]
In stars more massive than the sun, the core temperature is hotter, which allows for fusion of more complex elements.

Most of the fusion occurs in the core.

In stars more massive than the sun, fusion continues through Deuterium, Carbon, and finally reaching iron/nickel.

Up to this point, the fusion reaction was endothermic, which means that the energy expended to produce the fusion reaction was exceeded by the energy produced in the reaction.

Fusion past iron is exothermic, and therefore the star will be able to survive by fusing elements heavier than iron.

After the core is almost entirely iron, the star is no longer in the Main Sequence.

So, fusion in stars more massive than the sun continue fusing until the core is almost entirely <em>iron</em>.
3 0
3 years ago
(NEED HELP PLEASE) A physics student goes to the roof of the school, 24.15 m above the ground, and drops a pumpkin straight down
slavikrds [6]

Answer:

t = 2.2 s

Explanation:

Given that,

Height of the roof, h = 24.15 m

The initial velocity of the pumpkin, u = 0

We need to find the time taken for the pumpkin to hit the ground. Let the time be t. Using second equation of kinematics to find it as follows :

h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 24.15}{9.8}} \\\\t=2.22\ s

So, it will take 2.22 s for the pumpkin to hit the ground.

7 0
3 years ago
What pushes against gravity in: a main sequence star, a white dwarf, a neutron star, and a black hole? electron degeneracy, neut
Inga [223]

Answer:

heat pressure, electron degeneracy, neutron degeneracy, and nothing

Explanation:

Main Sequence Star: It is a star in which nuclear fusion is happening in the core of the star. Hydrogen molecules fuse together to generate Helium. This nuclear fusion generates outward gas pressure and radiation pressure which balances the inward gravity thus creating an equilibrium which keeps the stars in shape.

White dwarf: It is the end stage of a medium sized star like the Sun. Outer layers of the star are thrown in the form a shell/bubble leaving a small and dense core in the center called as white dwarf. This core consists of carbon and oxygen. Nuclear fusion doesn't occur in the core of white dwarfs. The inward gravity is balanced by the electron degeneracy pressure. Thus these stars will keep on radiating the remaining heat and will turn in to a black dwarf at the end.

Neutron Star: This is the end stage of a supermassive star (1-3 times the mass of the Sun). At the last stage of the life the core collapses. In these stars the inward gravity is so huge that the pressure overcomes the electron degeneracy pressure and crushes together the electron and proton to form neutron. The neutron then stops the collapse and balances the inward gravity.

Black Hole: This is the end stage of a hyper massive stars weighing more than 3 times the mass of the Sun. The inward gravitational force is so huge that even the neutrons are not able to stop the collapse the core. thus the mass of the star collapses into a very small area of immense gravity. There is nothing that can balance this inward gravity.

3 0
3 years ago
A meteoroid is traveling east through the atmosphere at 18. 3 km/s while descending at a rate of 11.5 km/s. What is its speed, i
Annette [7]

Answer:

The speed of meteoroid is 21.61 km/s in south-east.

Explanation:

Given that,

A meteoroid is traveling through the atmosphere at 18.3 km/s. while descending at a rate of 11.5 km/s it means 11.5 km/s in south.

We need to draw a diagram

Using Pythagorean theorem

AC^2=AB^2+BC^2

AC^2=(18.3)^3+(11.5)^2

AC=\sqrt{(18.3)^2+(11.5)^2}

AC=21.61\ km/s

Hence, The speed of meteoroid is 21.61 km/s in south-east.

6 0
3 years ago
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