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3 years ago

A material that provides little or no resistance to the flow of electric current is called a/an

2 answers:

5 0

I think the correct answer from the choices listed above is option B. <span>A material that provides little or no resistance to the flow of electric current is called a conductor since a conductor function to let electricity flow so it should have less resistance.</span>

GarryVolchara [31]3 years ago

3 0

Conductor .......................

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What do we call point E

vazorg [7]

Focal point of reflection

5 0

3 years ago

A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi

Airida [17]

Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

$F_{net} = F_{1} + F_{2} = 0$

So,

$\frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0$

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

$\frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}$

On dividing both sides of the equation by G.m.M, we get the following.

$\frac{1}{(1 - x)^{2}} = \frac{3}{x^{2}}$

$x^{2} = 3 - 6x + 3x^{2}$

0 = $3 - 6x + 2x^{2}$

Using the formula, $\frac{-b \pm \sqrt{(b)^{2} - 4ac}}{2a}$ the value of x comes out to be equal to +2.37 (not usabale) and -0.634 (usable).

Hence, we can conclude that the third mass will be located 0.634 meters away from the 3 m mass.

7 0

3 years ago

awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall

pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

$KE = 6.66 J$

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

$m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}$

now plug in all values in it

$1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22$

so we have

$3.01 = 0.375v_1 + 0.927v_2$

similarly in Y direction we have

$m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}$

now plug in all values in it

$0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22$

so we have

$0 = 0.927v_1 - 0.375v_2$

$v_2 = 2.47 v_1$

now from 1st equation we have

$3.01 = 0.375 v_1 + 0.927(2.47 v_1)$

$v_1 = 1.13 m/s$

$v_2 = 2.78 m/s$

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

$KE = \frac{1}{2}(1.47)(3.01^2)$

$KE = 6.66 J$

5 0

4 years ago

An object is moving with an initial velocity of 9m/s. It accelerates at a rate 1.5m/sec2 over a distance of 20m. What is it’s ne

puteri [66]

Answer:

11.87

Explanation:

final velocity^2= initial velocity ^2+ 2* Acceleration* distance

Final Velocity^2= 9*9+2*1.5.20

final velocity^2 = 141

final velocity = 11.87

4 0

4 years ago

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is

Brilliant_brown [7]

Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative Precipitation

Low Normal High

Do nothing -100 100 300

Expand 350 500 200

Build new 750 300 0

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is EVPI (Expected value of Perfect Information)?

A. $140,000

B. $170,000

C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

The expected long run profits are for

Low Normal High

Do nothing -100*0.3 100*0.2 300*0.5 = 140

Expand 350*0.3 500*0.2 200*0.5 = 305

Build new 750*0.3 300*0.2 0*0.5 = 285

Therefore the expected long run profits are

$140,000

$305,000

$285,000

Based on his selected option being either to build new or to expand, the most profitable option is to expand

=$305,000

EVPI = EPPI-EMV =$170,000

7 0

3 years ago