The answer is magnet away from the coil
From conservation of energy, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately
The given weight of Elliot is 600 N
From conservation of energy, the total mechanical energy of Elliot must have been converted to elastic potential energy. Then, the elastic potential energy from the spring was later converted to maximum potential energy P.E of Elliot.
P.E = mgh
where mg = Weight = 600
To find the height Elliot will reach, substitute all necessary parameters into the equation above.
250 = 600h
Make h the subject of the formula
h = 250/600
h = 0.4167 meters
Therefore, the height he will reach when he has gravitational potential energy 250J is 0.42 meters approximately
Learn more about energy here: brainly.com/question/24116470
Answer:
The magnetic field will be , '2d' being the distance the wires.
Explanation:
From Biot-Savart's law, the magnetic field () at a distance '' due to a current carrying conductor carrying current '' is given by
where '' is an elemental length along the direction of the current flow through the conductor.
Using this law, the magnetic field due to straight current carrying conductor having current '', at a distance '' is given by
According to the figure if '' be the current carried by the top wire, '' be the current carried by the bottom wire and '' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by symbol.
Given and
Therefore, the magnetic field () at 'P' due to the top wire
and the magnetic field () at 'P' due to the bottom wire
Therefore taking the value of the net magnetic field () at the midway between the wires will be
Answer:
Explanation:
On both sides of the film , the mediums have lower refractive index.
for interfering pattern from above , for constructive interference of reflected wave from both sides of the film , the condition is
2μt = ( 2n +1 ) λ / 2
μ is refractive index of film ,t is thickness of film λ is wavelength of light
n is order of fringe
for minimum thickness
n = 0
2μt = λ / 2
t = λ / 4μ
= 670 / 1.75 x 4
= 95.71 nm .