1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Len [333]
3 years ago
13

Which of the following is a nonrenewable energy source?

Chemistry
2 answers:
Tems11 [23]3 years ago
5 0
A - Nuclear energy is non-renewable
pickupchik [31]3 years ago
3 0
Nuclear energy is not renewable
You might be interested in
Semimetals is a term which refers to what
zvonat [6]

Answer:

Metalloids, also known as semimetals are elements containing properties similar and midway between metals and nonmetals. They are found to divide the periodic table between the metals on the left and the nonmetals on the right. Metalloids often have the following properties: could be dull or shiny.

3 0
3 years ago
Read 2 more answers
If the volume of the original sample in Part A ( P1 = 242 torr , V1 = 27.0 L ) changes to 80.0 L , without a change in the tempe
Brrunno [24]

The new pressure is 81.675 torr

Since temperature and moles are held constant, we use Boyle's Law:

A gas law known as Boyle's law asserts that a gas's pressure is inversely proportional to its volume when it is held at a fixed temperature and of a given mass.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another.

The Anglo-Irish chemist Robert Boyle proposed Boyle's law in the year 1662.

P1V1=P2V2. Simply plug in your values. The units can remain in torr. Converting to atmospheres is not needed.

(242 torr)(27.0 L)=P2(80.0 L)

P2=[(242)(27)]/80 = 81.675 torr

Hence The new pressure is 81.675 torr

Learn more about Boyle's Law here

brainly.com/question/26040104

#SPJ4

3 0
2 years ago
Suppose 15.00 mL of 3.0 x 10^{-6} M Fe(NO3)3 is added to 15.00 mL of 3.0 x 10^ –4 M KIO3. Will a precipitate form? Explain why.
matrenka [14]
It is 30292
2 \times 2 \sqrt[ > ]{?}
5 0
3 years ago
Which of the following describes what happens in a chemical reaction
Rus_ich [418]
Is there meant to be a photo here? there are no options so we can’t answer the question.
5 0
3 years ago
Identify the nuclide that would be formed from the alpha particle emission of Fm-257.
Elodia [21]

Answer: 1) The nuclide formed from the alpha decay of _{100}^{257}\textrm{Fm} is _{98}^{253}\textrm{Cf}

2) The nuclide formed from the beta-minus decay of _{98}^{253}\textrm{Cf} is _{99}^{253}\textrm{Es}

Explanation:

1) For alpha-decay

In this process, alpha particle is released.

Equation follows:

_{100}^{257}\textrm{Fm}\rightarrow _{98}^{253}\textrm{Cf}+_2^4\alpha

The nuclide formed is _{98}^{253}\textrm{Cf}

2) For beta-minus decay

In this process, a neutron is converted into a proton and an electron.

Equation follows:

_{98}^{253}\textrm{Cf}\rightarrow _{99}^{253}\textrm{Es}+_{-1}^0\beta

The nuclide formed is _{99}^{253}\textrm{Es}

5 0
3 years ago
Other questions:
  • How many moles of mgs2o3 are in 193 g of the compound?
    14·1 answer
  • Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8). When 1.025 g of naphthalene is burned in a bomb calorim
    13·1 answer
  • Why is water able to dissolve salts such as sodium chloride
    11·1 answer
  • How r fossil fuel helpful <br> Plss help ill give brainliest
    10·2 answers
  • How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.
    15·2 answers
  • Look at the diagram of a fuel cell used to power a motorized vehicle. A fuel cell with 2 vertical objects labeled A and B connec
    7·2 answers
  • Strong hydrochloric acid can dissolve many substances. Which type of hazardous waste would this acid be?
    7·1 answer
  • How many moles of NH3 are there in 77.5 g of NH3?
    8·1 answer
  • Hecking skills activated
    6·2 answers
  • A + B = AB
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!