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babymother [125]

3 years ago

14

The plates on a vacuum capacitor have a radius of 3.0 mm and are separated by a distance of 1.5 mm. What is the capacitance of t

his capacitor?

1 answer:

Mkey [24]3 years ago

6 0

Link provided in other answer is a SCAM, don’t click on the link !!!!

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You walk forward at 1.5 m/s for 8s. Your friend decides to walk faster and starts out at 2.0 m/s for the first 4 s. Then she slo

Troyanec [42]

The first thing you should know is that the distance is equal to the speed per time.
Therefore if You walk forward at 1.5 m / s for 8s
d = 1.5t [0,8] s
Your friend decides to walk faster and starts at 2.0 m / s for the first 4 s.
d = 2t [0,4] s
Then she slows down and walks forward at 1.0 m / s for the next 4s
d = t + 4 [4,8] s
Who walked farther?
They both walked the same distance
12 meters

6 0

3 years ago

An ideal gas occupies a volume of 0.60 m^3 at 5.0 ATM and 400. K. What volume does it occupy at 4.0 ATM and a temperature of 200

sattari [20]

Answer:0.375m3

Explanation:This is general gas law. The expression is given by P1V1/T1 =P2V2/T2

we are looking for V2 so let's make it the change of subject of formula

V2= P1xV1xT2/P2T1

= 5 x 0.6 x 200/400 x 4

= 0.375m3

7 0

3 years ago

To see how deep a well is you drop a rock in. The rock hits the water 10 seconds later.

Karolina [17]

Answer:

490m

Explanation:

Given parameters:

Time taken = 10s

Unknown:

Depth of the well = ?

Solution:

To find the depth of the well, we apply the appropriate motion equation:

h = ut + $\frac{1}{2}$ gt²

h is the depth

u is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

t is the time taken

Input the parameters and solve;

The ball was dropped from rest; u = 0

h = $\frac{1}{2}$ gt²

h = $\frac{1}{2}$ x 9.8 x 10² = 490m

6 0

3 years ago

Which of the following is a disadvantage of using solar energy

Veseljchak [2.6K]

Please provide options.

7 0

3 years ago

A Carnot engine whose high-temperature reservoir is at 620 K takes in 550 J of heat at this temperature in each cycle and gives

Novosadov [1.4K]

(a) W=217 J is the amount of mechanical work done by engine during each cycle.

(b) temperature of the low-pressure reservoir Tc=378K

(c) thermal efficiency of the cycle (e)=0.39=39%

Calculation:

For part (a)

We need to calculate the mechanical work W the engine does.

W = IQHI — IQcl .....................eq(1)

Putting the given values of QH and QC into eq(1) we get

the mechanical work of the engine W

W = 550 - 335

W=217 J

For part (b)

We need to determine the temperature of low temperature reservoir Tc

IQc|/|Qh| =TC/TH

for Tc

Tc=(IQc|/|Qh|)*TH

Now putting the values, we get

Tc= 620K (335/ 550.1)

Tc=378K

For part (c)

We need to find the thermal efficiency (e) of the cycle

e=1-TC/TH

e=1-(378/620)

e=0.39=39%

<h3>What is mechanical energy?</h3>

The energy that an object possesses as a result of its motion or position is known as mechanical energy. Kinetic energy, or the energy of motion, and potential energy are two types of mechanical energy (stored energy of position).

To learn more about mechanical work visit:

brainly.com/question/17190305

#SPJ4

Correct question:

A Carnot engine whose high-temperature reservoir is at 620 k takes in 550 J of heat at this temperature in each cycle and gives up 335 J to the low temperature reservoir.

(a) How much mechanical work does the engine perform during each cycle?

(b) What is the temperature of the low-pressure reservoir?

(c)What is the thermal efficiency of the cycle?

3 0

1 year ago