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3 years ago

What is the average velocity of an arrow that travels 12 m [E] in 0.15 s?

1 answer:

6 0

Velocity is defined as Distance divided by Time.
In other words, V = D/T.

Now that we have our formula, we can solve.
Let's plug in the numbers we have.

We have 12m [East (direction not necessary when solving yet)] for our distance, and 0.15s as our time.

Divide the distance (12 /) by the time (0.15)
12 / 0.15 = 80.

Your velocity is 80 m/s [E]

I hope this helps!

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Explanation:

from the question we are told that

The displacement of a mass on a spring in simple harmonic motion is A/2 from the equilibrium position

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$PE = \frac{1}{ 2} * k * [ \frac{A}{2} ]^2$

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=> $KE = \frac{1}{2} * k * A^2 - \frac{1}{8} * k * A ^2$

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