Answer:
ω = 630.2663 = 630[rad/s]
Explanation:
Solution:
- We can tackle this question by simple direct proportion relation between angular speed for the disk to rotate a cycle that constitutes 20 holes. We will use direct relation with number of holes per cycle to compute the revolution per seconds i.e frequency of speed f.
1rev(20 hole) -> 20(cycle)/rev
2006.2(cycle) -> f ?
f = 2006.2/20 = 100.31rev at second
- The relation between angular frequency and angular speed is given by:
ω = 2πf
ω = 2*3.14*100.31
ω = 630.2663 = 630[rad/s]
<span>The temperature of water will boil at one hundred degrees celsius when the external pressure is at 17.5 torr. Essentially, it is based off of the vaporizing of heat, as well as the gas constant. This is a matter of solving a physics equation and breaking down the factors that will affect the boiling point.</span>
Answer:
l these errors believe that the speed of the system is less than that calculated
Explanation:
When we carry out any measurement in addition to the magnitude, the sources of uncertainty must also be analyzed.
We can have random uncertainties, correspondin
g to momentary errors, for example early warps during medicine, parallax errors, errors in the starting and ending points of the movement; I mean every possible random error. This error is the one that is analyzed and calculated in the statistical equations
There is another source of error, the systematic ones, these are much more complicated, they can be an error in the pendulum length, friction in the pendulum movement mechanism, deformities in the support systems, this errors are not analyzed by the statistic, in general They discover by looking at the results and comparing with the tabulated or real ones.
tith the explanation we see that the errors described are systematic.
In general these errors believe that the speed of the system is less than that calculated
Answer:
d = 2083.33 m
Explanation:
Given that,
Acceleration of the train, a = 0.15 m/s²
The initial speed of the car, u = 0\
Final velocity, v = 25 m/s
We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :
So, the minimum distance is 2083.33 m
Answer:
Period of oscillation = 1.33 seconds
Explanation:
The period of oscillation is given by:
T = 2π√[I/(MgL)]
for I = 2MR² and L = R,
Given: L = 0.22m = R
T = 2π√[2R/g]
T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]
T = 6.284 Sqrt(0.44/9.8)
T = 6.284 Sqrt(0.0449)
T = 6.284 × 0.2119
T = 1.33 sec
