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Harlamova29_29 [7]
3 years ago
11

A neutral atom has two, eight, eight electrons in its first, second, and third energy levels. this information ________. does no

t tell us about the atomic number of the element does not tell us about the chemical properties of the element does not tell us about the atomic mass of the element does not tell us about the size of the element
Chemistry
2 answers:
olga55 [171]3 years ago
4 0
This info tells us if it stable or not and it tells us how many electrons it need to be stable.
tangare [24]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Atomic mass is the summation of no. of protons and average number of neutrons present in an element.

On the other hand, atomic number is the sum of total number of protons only which are present in an element.

Each element of a periodic table has a different fixed number of protons. Knowing the number of protons or atomic number we do not get to know about the number of neutrons.

For example, atomic number of Na is 11 but it does not tell that Na also contains 12 neutrons.

Thus, we can conclude that when a neutral atom has two, eight, eight electrons in its first, second, and third energy levels. This information does not tell us about the atomic mass of the element.

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Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
Hoochie [10]

Answer:

\boxed{\text{CH$_{2}$}}

Explanation:

1. Calculate the mass of each element

\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}

2. Calculate the moles of each element

\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015

4. Round the ratios to the nearest integer

C:H = 1:2

5. Write the empirical formula

The empirical formula is \boxed{\text{CH$_{2}$}}

8 0
3 years ago
Question 2 (2 points)
poizon [28]

Answer:

m_w=439.2g

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}

Thus, by plugging in the data, we obtain:

m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g

Best regards!

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