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Harlamova29_29 [7]
3 years ago
11

A neutral atom has two, eight, eight electrons in its first, second, and third energy levels. this information ________. does no

t tell us about the atomic number of the element does not tell us about the chemical properties of the element does not tell us about the atomic mass of the element does not tell us about the size of the element
Chemistry
2 answers:
olga55 [171]3 years ago
4 0
This info tells us if it stable or not and it tells us how many electrons it need to be stable.
tangare [24]3 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Atomic mass is the summation of no. of protons and average number of neutrons present in an element.

On the other hand, atomic number is the sum of total number of protons only which are present in an element.

Each element of a periodic table has a different fixed number of protons. Knowing the number of protons or atomic number we do not get to know about the number of neutrons.

For example, atomic number of Na is 11 but it does not tell that Na also contains 12 neutrons.

Thus, we can conclude that when a neutral atom has two, eight, eight electrons in its first, second, and third energy levels. This information does not tell us about the atomic mass of the element.

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Calculate the number of oxygen atoms and its mass in 50g of CaCo3<br>​
xz_007 [3.2K]

The number of oxygen atoms = 3

Mass = 24 g

<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

  • Ca = 1
  • C = 1
  • O = 3

So the number of oxygen atoms = 3

mass of Oxygen :

\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g

5 0
3 years ago
Calculate the mass, in grams, of cucl2 (mw = 134.452 g/mol) required to prepare 250.0 ml of a 6.11 % w/v cu2 (mw = 63.546 g/mol)
Sever21 [200]

6.11% w/v of Cu2+ implies that 6.11 g of Cu2+ is present in 100 ml of the solution

therefore,  250 ml of the solution would have: 250 ml * 6.11 g/100 ml = 15.275 g

# moles of Cu2+ = 15.275 g/63.546 g mole-1 = 0.2404 moles

1 mole of CuCl2 contain 1 mole of Cu2+ ion

Hence, 0.2404 moles of Cu2+ would correspond to 0.2404 moles of CuCl2

Molar mass of CuCl2 = 134.452 g/mole

The mass of CuCl2 required = 0.2404 moles * 134.452 g/mole = 32.32 grams

6 0
3 years ago
What volume (in mililiters) of oxygen gas is required to react with 4.03 g of my at stp
goldenfox [79]

You must use 1880 mL of O₂ to react with 4.03 g Mg.

A_r: 24.305

         2Mg + O₂ ⟶ 2MgO

<em>Moles of Mg</em> = 4.03 g Mg × (1 mol Mg/24.305 g Mg) = 0.1658 mol Mg

<em>Moles of O₂</em> = 0.1658 mol Mg × (1 mol O₂/2 mol Mg) = 0.082 90 mol O₂

STP is 25 °C and 1 bar. At STP, 1 mol of an ideal gas has a volume of <em>22.71 L</em>.

<em>Volume of O₂</em> = 0.082 90 mol O₂ × (22.71 L O₂/1 mol O₂) = 1.88 L = 1880  mL

4 0
3 years ago
Viruses are not considered living things because they are not cellular and they __________.
Virty [35]
Must have host cell to reproduce
8 0
3 years ago
Which statement best describes the formula equation cl1(g) + 2kbr(aq) —&gt; 2kcl(aq)+br2(i)
Zigmanuir [339]

Answer:

The chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Explanation:

Chemical equation:

Cl₂(g) + KBr (aq) → KCl (aq) + Br₂(l)

Balanced chemical equation:

Cl₂(g) + 2KBr (aq) → 2KCl (aq) + Br₂(l)

This equation showed that the chlorine gas and potassium bromide solution react to form liquid  bromine and potassium chloride solution.

Chlorine is more reactive than bromine it displace the bromine from potassium and form potassium chloride solution.

The given equation is balanced and completely hold the law of conservation of mass.

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

8 0
3 years ago
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