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sveticcg [70]
3 years ago
12

A 255 ml gas sample contains argon and nitrogen gas at a temperature of 65 oc. the total pressure of the sample is 725 mmhg, and

the partial pressure of argon is 231 mmhg. what mass of nigrogen gas is present in the sample?
Chemistry
1 answer:
Serhud [2]3 years ago
6 0
We calculate first for the number of moles of gases in the sample through the ideal gas equation.
                                       n = PV/RT
      n = (725 mmHg/760 mmHg/atm)(0.255 L) / (0.0821 L.atm/mol.K)(65 + 273.15)  
                                       n = 8.76 x 10^-3 mol
Then, we calculate for the mol N2 using the ratio of the pressure.
                          n N2 = (8.76 x 10^-3 mols)(231 mmHg/725 mmHg)
                           n N2 = 2.79 x 10^-3 moles
Then, multiply the value with the molar mass of N2 which is 28 grams per mol giving us the answer of 0.078 grams. 
                                   
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Help asap
alisha [4.7K]

Answer: Option (b) is the correct answer.

Explanation:

It is known that metals are the species which readily lose an electron and tend to attain a positive charge.

For example, atomic number of sodium is 11 and its is an alkali metal. It electronic distribution is 2, 8, 1.

And, in order to attain stability it readily loses an electron and thus it become Na^{+} ion.

Also, it is known that species which tend to transfer or donate their valence electrons to other atoms tend to form ionic bond and the compound formed is known as ionic compound.

Therefore, we can conclude that the statement metal atoms held together by ionic bonds best describes a metal solid.

4 0
4 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
Sally has constructed a concentration cell to measure Ksp for MCln. She constructs the cell by adding 2 mL of 0.05 M M(NO3)n to
hram777 [196]

Answer:

0.1056 mole

Explanation:

As Sally knows that the charge on the metal ion is n = +2

$MCl_n=MCl_2$

In that compartment $[M^{n+}]=[m^{2+}]=8.279 \ M$

The volume of the $MCl_n$ taken in that compartment = 6.380 mL

So, the number of moles of $M^{2+} = 8.279 \times 6.380$

                                                      = 52.82 m mol

                                                      = 0.05280 mol

$MCl_n \rightarrow M^{n+}+nCl^-$

But n = 2

Therefore, moles of $Cl^-$ = 2 x moles of $M^{n+}$

                                       = 2 x 0.05282

                                       = 0.1056 mole

3 0
3 years ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
What is the molarity of a KOH solution if it requires 20 milliters of 2.0m HCL to exactcly neutalize 20 milliters of the KOH sol
soldier1979 [14.2K]
HCL 2.0x 3.6790= KOH SOLITION
6 0
3 years ago
Read 2 more answers
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