Answer:
Positive: a and b
Negative: c
Explanation:
The entropy (S) is the measure of the randomness of the system, and it intends to increase. The randomness can be determined by the energy of the molecules, their velocity and how distance they are between the other molecules.
When the entropy increases, ΔS is positive, when the entropy decreases, ΔS is negative. So, when gasoline mix with air in a car engine, the process intends to continue, the randomness increases and ΔS is positive. When hot air expands, the distance between the molecules increases, so ΔS is positive.
But, when humidity condenses, the molecules stay closer, so there's a decrease in the randomness, then ΔS is negative.
It’s g cause it’s closest to 10 which would make 40
Answer:
D +405.0kJ mol-¹
Explanation:
Since bond energy is the energy required to break a bond, the energy of dissociation of X₂H₆ = +2775 kJmol⁻¹.
Since there is one X-X bond and six X-H bonds,
Bond energy of one X-X bond + Bond energy of six X-H bonds = energy of dissociation of X₂H₆.
Since bond energy of one X-H bond = 395 kJ mol⁻¹, then
Bond energy of one X-X bond + Bond energy of six X-H bonds = energy of dissociation of X₂H₆
Bond energy of one X-X bond + 6 × one X-H bond = +2775 kJmol⁻¹.
Bond energy of one X-X bond + 6 × 395 kJ mol⁻¹ = +2775 kJmol⁻¹.
Bond energy of one X-X bond + 2370 kJ mol⁻¹ = 2775 kJmol⁻¹
Bond energy of one X-X bond = 2775 kJmol⁻¹ - 2370 kJ mol⁻¹
Bond energy of one X-X bond = +405 kJmol⁻¹
Answer:
Orbitals give a probability map of where it is likely to find an electron in an atom.
Explanation:
Wave mechanical model of the atom suggests that an atom contains a nucleus which has positively charged protons and neutral neutrons.
The outer part of the atom is mostly empty.
The negatively charged electrons are located in outer orbitals.
The true statement is :
Orbitals give a probability map of where it is likely to find an electron in an atom.
HNO3 is a strong acid and NaOH is a
strong base. An equal number of moles of
each will create a neutral solution.
(.1500L)(.100M NaOH) = .01500 moles
NaOH, and therefore .015 moles OH-
.01500 moles H+ = .01500 moles HNO3 =
(.120M HNO3)(volume HNO3)
volume HNO3 = .125L HNO3, or 125mL
HNO3
