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icang [17]
3 years ago
11

Food in the stomach is broken down by powerful acids and turned into?

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
8 0
<span>food is broken down bu powerful acids in the stomach its turned into chyme The food is broken into chyme so it became small enough to passes small intenstine in our stomach during the digestive systems. Without it, the foods will not be able to find its own way out through the secretion system</span>
zheka24 [161]3 years ago
4 0
<span>In this particular item, we are to determine how we call the acidic fluid-like substance that is formed after the food in the stomach is broken down by a powerful acid. The answer to this question is CHYME. The powerful acid that is referred in this item is more specifically gastric juices. </span>
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Give the name of the reaction that achieves the theoretical limits with respect to free energy in thermodynamics.a. reversible r
Assoli18 [71]

Answer:

The correct option is: a. reversible reaction

Explanation:

In thermodynamics, Gibb's free energy is the quantitative measure of the <u>spontaneity or feasibility </u>of a chemical reaction, at fixed temperature and pressure.

It can also be described as the <u>maximum available work obtained from a closed system</u>. This maximum work can only be achieved in a reversible process, <u>at fixed pressure and temperature.</u>

<u>The Gibb's free energy (ΔG) is given by</u>: ΔG = ΔH - T.ΔS

8 0
3 years ago
HELP!
MAVERICK [17]

Answer:

C

Explanation:

energy cannot be created or destroyed like solar energy for instance. it is already energy because it comes from the sun and for other reason.

Hope this helps!

4 0
3 years ago
How many atoms are in 1 mole of hydrogen
Angelina_Jolie [31]
There are TWO atoms in one molecule of hydrogen.
8 0
3 years ago
Calculate the mass of H2OH2O produced by metabolism of 2.4 kgkg of fat, assuming the fat consists entirely of tristearin (C57H11
otez555 [7]

Answer:

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

Explanation:

2C_{57}H_{110}O_6+163O_2\rightarrow 114CO_2+110H_2O

Mass of fat = 2.4 kg = 2.4 × 1000 g = 2400 g

1 kg = 1000 g

Molar mass of fat = M

M = 57 × 12 g/mol + 110 × 1 g/mol+ 6 × 16 g/mol = 890 g/mol[/tex]

Moles of fat = \frac{2400 g}{890 g/mol}=2.6966 mol

According to reaction , 2 moles of fat gives 110 moles of water. Then 2.6966 moles of fat will give  ;

\frac{110}{2}\times 2.6966 mol=148.31 mol of water

Mass of 148.31 moles of water ;

148.31 mol × 18 g/mol = 2,669.58 g

2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.

8 0
3 years ago
If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
Elodia [21]

Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M

Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂

We will use the following expression.

Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

3 0
3 years ago
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