The net ionic equation is
Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)
<em>Molecular equation
:</em>
Cu(s) + 4HNO₃(aq) ⟶ Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(ℓ)
<em>Ionic equation:
</em>
Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)
<em>Net ionic equation
</em>
Cu(s) + 4H⁺(aq) + 4NO₃⁻(aq) ⟶ Cu²⁺(aq) + 2NO₃⁻(aq) + 2NO₂(g) + 2H₂O(ℓ)
<em>Note</em>: The net ionic equation is <em>the same as </em>the ionic equation because there are <em>no common ions</em> to cancel on opposite sides of the arrow.
Moles = weight in grams / molecular weight.
So I would divide the "grams of barium" by its molecular weight (which is 137.3) to get "moles of barium". :)
<span>what volume of ammonia must you measure?
1.50 moles NH3 ( 22.4 L / 1 mole ) = 33.6 L NH3 should be measured
</span><span>how many molecules of nacl are in 23.40 grams nacl
23.40 g NaCl ( 1 mol / 58.44 g) (6.022 x 10^23 molecules / 1 mol ) = 2.4113 x 10^23 molecules
Hope these answer the questions. Have a nice day.</span>
I really don't know and it sucks when i need help and people are giving me false answers.
