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3 years ago

A family has a Y-linked disease that affects the father. What is the chance of a male offspring inheriting the same disease?

Chemistry

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer: The correct answer is A) 100%.

Y linked disease is the one that is caused by genes present on the Y chromosomes. Females have XX and males have XY chromosomes that determine their gender. This means that Y chromosome is only present in males and all male offsprings inherit this chromosome from their father. Whereas, female offsprings inherit X chromosome ( from each parent).

As per the question, family has Y linked disease that affects father.

Thus, there will be 100% chances of inheriting this disease by the male offspring.

Tom [10]3 years ago

4 0

Remember that males have an x and y chromosome, while women have two x chromosomes.

This means that a female offspring (daughter) inherits her father's only x chromosome and one of her mother's x chromosomes, while a male will receive his father's y chromosome and one of his mother's x chromosomes.

This means that the boy will necessarily inherit his dad's Y chromosome, and any diseases that it carries.

The chance of a male offspring inheriting the disease is
A) 100%

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Charles's law is an experimental gas law that shows the relationship between the temperature of a gas and its corresponding volu

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Answer:

The correct answer is (b)

Explanation:

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4 years ago

The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad

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Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

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As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

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In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

$2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}$

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$2x+1.128x=566$

$3.128x=566$

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The radius of Na⁺ ion = (0.564x) pm = (0.564 × 181) pm =102.084 pm ≈ 102 pm

Thus, the radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

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