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Pavlova-9 [17]
3 years ago
13

Give the outer electron configuration for each of the following columns in the periodic table. 1A,2A,5A,7A Express your answer a

s a string without blank space between orbitals. For example, the outer electron configuration for the column 4A, ns2np2, should be entered as ns^2np^2.
Chemistry
1 answer:
Oliga [24]3 years ago
4 0

Answer:

1A:  ns^1

2A: ns^2

5A: ns^2np^3

7A: ns^2np^5  

Explanation:

<u>According to IUPAC, the columns 1A, 2A, 5A, and 7A correspond to the groups, 1, 2, 15 and 17, respectively</u>.

The outer electron configuration of these columns are the following:

Column    Outer electron configuration

1A              ns^1

2A             ns^2

5A             ns^2np^3

7A             ns^2np^5  

Therefore, for the column 1A the s orbital has only one electron, for the column 2A has the s orbital completed with 2 electrons, for the column 5A the number of electrons in the s orbital is complete (2) and the number of electrons in the p orbital is 3, for the column 7A the s orbital has 2 electrons and the p orbital has 5 electrons.            

I hope it helps you!                      

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The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

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<h3>How to determine the mass of the fluorine gas</h3>
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Mass = mole × molar mass

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Mass of fluorine gas = 38 g

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KE = ½mv²

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KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

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