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3 years ago

3 cases where kinetic energy become potential energy

2 answers:

8 0

-- Toss a rock straight up. The kinetic energy you give it
with your hand becomes potential energy as it rises.
Eventually, when its kinetic energy is completely changed
to potential energy, it stops rising.

-- When you're riding your bike and going really fast, you come
to the bottom of a hill. You stop pedaling, and coast up the hill.
As your kinetic energy changes to potential energy, you coast
slower and slower. Eventually, your energy is all potential, and
you stop coasting.

-- A little kid on a swing at the park. The swing is going really fast
at the bottom of the arc, and then it starts rising. As it rises, the
kinetic energy changes into potential energy, more and more as it
swings higher and higher. Eventually it reaches a point where its
energy is all potential; then it stops rising, and begins falling again.

Taya2010 [7]3 years ago

6 0

<span>Some things that you could say are: 1. When a parked lorry starts to move; 2. When a stone is dropped from a building; 3. When a marathon runner starts to run.</span>

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The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)

v = ? is the orbital velocity of the Hubble telescope

Re-arranging the equation and substituting numbers, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24} kg)}{6.99\cdot 10^6 m}}=7548 m/s=7.55 km/s$

6 0

3 years ago

A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____

Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$ , f = focal length of the mirror

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}$

v = -8.57 cm

The magnification of a mirror is given by,

$m=\dfrac{-v}{u}$

$m=\dfrac{-(-8.57)}{-20}$

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

5 0

3 years ago

A scientist prepares a colloidal solution and pours it into a glass tank. She then flashes a beam of white light into one end of

balu736 [363]

The answer is C) <span>The higher frequencies of visible light were scattered by the colloid particles.</span>

5 0

2 years ago

Read 2 more answers

A materials density is the same , no matter how large or small the sample is or what it’s shape is as long as it is solid unifor

Scorpion4ik [409]

Answer:

See the explanation below

Explanation:

Density is defined as the relationship between mass and volume, i.e. the following equation can be used:

density = m/v

where:

density [kg/m^3]

m = mass [kg]

v = volume [m^3]

If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.

m = density*v

To understand this concept more clearly, let's use the following example:

We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.

1000 = m /1

m = 1000*1 = 1000 [kg]

Now if we have 500 kilograms of water, that would pass with the volume so that the density remains constant.

1000 = 500/v

v = 500/1000

v = 0.5 [m^3]

We can see that the volume of water has halved. Since the mass of water was reduced by half. That is, the relationship between mass and volume is proportional to the density of the material or substance.

8 0

3 years ago

The magnetic field lines of a bar magnet spread out from the north end to the south end. South end to the north end. Edges to th

Gwar [14]

<h3><u>Answer;</u></h3>

the north end to the south end.

<h3><u>Explanation;</u></h3>

Magnetic field lines from a bar magnet form lines that are closed. The direction of magnetic field is taken to be outward from the North pole of the magnet and in to the South pole of the magnet.
A magnetic field refers to the area surrounding a magnet where a force is exerted on certain objects. These lines are spread out of the north end of the magnet.
The magnetic field lines resemble a bubble.

3 0

3 years ago

Read 2 more answers