Position will be measured on the y-axis and time measured on the x-axis. Usually y is meters and x is time so when you take the slope (velocity or speed) y/x = m/s.
Answer: 13 m/s
Explanation: The two vectors form a 5-12-13 right triangle. the magnitude of their resultant is the hypotenuse, which is 13 m/s.
A liquid to gas phase change is the result of particles moving more quickly.
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Answer: ![= (1.31i+2.42j)m/s\\](https://tex.z-dn.net/?f=%3D%20%281.31i%2B2.42j%29m%2Fs%5C%5C)
Explanation:
GIVEN DATA:
![m1 = 2.03kg\\m2 = 3.02kg\\v1 = 1.90 i - 2.91 j) m/s\\v2 = (0.92 i -6.00 j) m/s\\](https://tex.z-dn.net/?f=m1%20%3D%202.03kg%5C%5Cm2%20%3D%203.02kg%5C%5Cv1%20%3D%201.90%20i%20-%202.91%20j%29%20m%2Fs%5C%5Cv2%20%3D%20%280.92%20i%20-6.00%20j%29%20m%2Fs%5C%5C)
<u><em>Solution:</em></u>
the velocity for centre of the mass
![vcm= \frac{m1v1+m2v2}{m1+m2}](https://tex.z-dn.net/?f=vcm%3D%20%5Cfrac%7Bm1v1%2Bm2v2%7D%7Bm1%2Bm2%7D)
input the values into the formula.
![vcm=\frac{(2.03)(1.90 i - 2.91 j)+(3.02)(0.92 i -6.00 j) }{2.03+3.02}](https://tex.z-dn.net/?f=vcm%3D%5Cfrac%7B%282.03%29%281.90%20i%20-%202.91%20j%29%2B%283.02%29%280.92%20i%20-6.00%20j%29%20%7D%7B2.03%2B3.02%7D)
open the bracket
![= \frac{3.86i-5.91j +2.78i+18.12j}{5.05}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B3.86i-5.91j%20%2B2.78i%2B18.12j%7D%7B5.05%7D)
collect like terms
![= \frac{6.64i+12.21j}{5.05}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B6.64i%2B12.21j%7D%7B5.05%7D)
![= (1.31i+2.42j)m/s](https://tex.z-dn.net/?f=%3D%20%281.31i%2B2.42j%29m%2Fs)
total momentum
![p= (m1+m2)vcm\\= (2.03+3.02) (1.31i+2.42j)\\= 5.05 (1.31i+2.42j)\\=(6.62i+12.22j)kg.m/s](https://tex.z-dn.net/?f=p%3D%20%28m1%2Bm2%29vcm%5C%5C%3D%20%282.03%2B3.02%29%20%281.31i%2B2.42j%29%5C%5C%3D%205.05%20%281.31i%2B2.42j%29%5C%5C%3D%286.62i%2B12.22j%29kg.m%2Fs)