Work is closely related to energy. The work-energy principle states that an increase in the kinetic energy of a rigid body is caused by an equal amount of positive work.
So they are both closely related to each other.
HOPE THIS HELPS
To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

= Coulomb's constant
q = Charge
r = Radius
At the same time

The values of variables are the same, then if we replace in a single equation we have this expression,

If we replace the values, we have finally that the charge is,




Therefore the potential energy of the system is 
Grapefruit juice. The more acidic something is the more h it has.
50 miles east. because the 30 miles north then south cancel each other out.
Answer:
Distance covered by B is 4 times distance covered by A
Explanation:
For an object in free fall starting from rest, the distance covered by the object in a time t is

where
s is the distance covered
g is the acceleration due to gravity
t is the time elapsed
In this problem:
- Object A falls through a distance
during a time t, so the distance covered by object A is

- Object B falls through a distance
during a time 2t, so the distance covered by object B is

So, the distance covered by object B is 4 times the distance covered by object A.