Question

Which of these elements has two electrons in its outer p orbitals?

Answer 1

Answer : The correct option is, Silicon (Si)

Explanation :

Element = Helium

Atomic number = Number of electrons = 2

The electronic configuration will be, $1s^2$

Element = Barium

Atomic number = Number of electrons = 56

The electronic configuration will be, $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^2$

Element = Nitrogen

Atomic number = Number of electrons = 7

The electronic configuration will be, $1s^22s^22p^3$

Element = Silicon

Atomic number = Number of electrons = 14

The electronic configuration will be, $1s^22s^22p^63s^23p^2$

Element = Sulfur

Atomic number = Number of electrons = 16

The electronic configuration will be, $1s^22s^22p^63s^23p^4$

From the electronic configurations, we conclude that the element silicon has two electrons in its valence 'p' orbital or outermost 'p' orbitals.

Hence, the correct option is, Silicon (Si)

Answer 2

Silicon (si) has two electrons in its outer p orbitals.

Explanation:

For the element of SILICON, you previously know that the atomic number shows the number of electrons. That indicates there are 14 electrons in a silicon atom. Looking at the design, you can see there are two particles in shell one, eight in shell two, and four in shell three. Si which is 4 elements from the left side of the table,first 2 electrons are s orbitals when next two electrons go to Si