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Pepsi [2]
3 years ago
6

Which of these elements has two electrons in its outer p orbitals?

Chemistry
2 answers:
gulaghasi [49]3 years ago
5 0

Answer : The correct option is, Silicon (Si)

Explanation :

Element = Helium

Atomic number = Number of electrons = 2

The electronic configuration will be, 1s^2

Element = Barium

Atomic number = Number of electrons = 56

The electronic configuration will be, 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^2

Element = Nitrogen

Atomic number = Number of electrons = 7

The electronic configuration will be, 1s^22s^22p^3

Element = Silicon

Atomic number = Number of electrons = 14

The electronic configuration will be, 1s^22s^22p^63s^23p^2

Element = Sulfur

Atomic number = Number of electrons = 16

The electronic configuration will be, 1s^22s^22p^63s^23p^4

From the electronic configurations, we conclude that the element silicon has two electrons in its valence 'p' orbital or outermost 'p' orbitals.

Hence, the correct option is, Silicon (Si)

ivanzaharov [21]3 years ago
4 0

Silicon (si) has two electrons in its outer p orbitals.

Explanation:

For the element of SILICON, you previously know that the atomic number shows the number of electrons. That indicates there are 14 electrons in a silicon atom. Looking at the design, you can see there are two particles in shell one, eight in shell two, and four in shell three. Si which is 4 elements from the left side of the table,first 2 electrons are s orbitals when next two electrons go to Si

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Match the following names of glassware with what you would use them for.
Valentin [98]

Answer:

A) Graduated pipette – Glassware used to accurately transfer small volumes.

B) Volumetric pipette – Glassware used to accurately transfer a small, single volume.

C) Beaker – Glassware best used when greater access to the contents is needed.

D) Buret – Glassware used to deliver a volume not known in advance.

E) Erlenmeyer flask – Glassware used to prevent splashing or evaporation.

F) Volumetric flask – Glassware used to make accurate solutions.

Explanation:

Graduated pipette – Glassware used to accurately transfer small volumes.

A graduated pipette is a pipette, which has a scale that shows its volume marked along the tube. It is used to transfer small volumes accurately.

Volumetric pipette – Glassware used to accurately transfer a small, single volume.

A volumetric pipette is a pipette, which has a ring like marking that is its calibrated volume. So it is used to transfer a single and small volume only. This pipette is used in volumetric analysis.

Beaker – Glassware best used when greater access to the contents is needed.

Beaker is the most widely used glassware in the laboratory. They are used to transfer large volume with less accuracy. They are of different sizes depends on the size of volumes ranging from 10 mL to 1000 mL.

Buret – Glassware used to deliver a volume not known in advance.

Buret is the most important glassware in the quantitative analysis. It has a glass tube with scale which measures the volume and a stopcock at one end from which the solvent is dispersed. It is used to measure the volume of the liquid during the titration in the quantitative analysis.

Erlenmeyer flask – Glassware used to prevent splashing or evaporation.

The most common names of Erlenmeyer flask are conical flask and titration flask. This flask has flat bottom, conical body and cylindrical neck which prevent splashing and evaporation. This flask is used in the titration process in the quantitative analysis. The solvent from the buret is delivered into the conical flask during the titration process.

Volumetric flask – Glassware used to make accurate solutions.

The volumetric flask is also an important glassware in the analytical laboratory. It is used to prepare standard solutions. It is a flask which has a ring like marking that is its calibrated volume. The mentioned volume of volumetric flask is calibrated to have accurate volume.

3 0
3 years ago
Balance the following reaction in KOH (under basic conditions). What are the coefficients in for C3H8O2 and KMnO4 in the balance
GrogVix [38]

Answer:

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Explanation:

We are given that  a reaction in which C_3H_8O_2 reacts with KMnO_4

We have to find the coefficient of each reactants in balanced reaction

3C_3H_8O_2(aq)+8KMnO_4(aq)\rightarrow 3C_3H_2O_4K_2(aq)+8MnO_2(aq)+2KOH+8H_2O

Coefficient is defined the constant  value multiplied with a reactant in a reaction.

Coefficient of C_3H_8O_2=3

Coefficient of KMnO_4=8

Coefficient of C_3H_2O_4K_2=3

Coefficient of MnO_2=8

Coefficient of H_2O=8

Coefficient of KOH=2

Hence, Coefficient of C_3H_8O_2=3 and coefficient of KMnO_4=8

7 0
3 years ago
How does the geosphere and biosphere interact
Vlada [557]

The geosphere, in turn, reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight (energy) from the atmosphere.

Explanation:

  • The geosphere, in return reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight energy from the atmosphere.
  • Scientists divide the planet into two the main components: the biosphere, which consists of all life.
  • The hydrosphere interacts with the geosphere when particles of water or rain cause land formations to erode.
  • biosphere is the part of the earth and its atmosphere capable of supporting life.
  • Geo sphere is the solid body of the earth.
  • Biosphere is the totality of living organisms and their environment.

6 0
3 years ago
At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
wariber [46]

Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

∴

\frac{23.09}{23.76}= x_i

x_i = 0.9718

x_i+x_2=1

x_2 = 1- x_i

x_2 = 1- 0.9718

x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

= 0.02901

NOW, Molarity =  \frac{moles of sea water}{mass of pure water }*1000

= \frac{0.02901}{18}*1000

= 0.001616*1000

= 1.616 M

As we assume that the sea water contains only NaCl, if NaCl dissociates to Na⁺ and Cl⁻; we have \frac{1.616}{2} =0.808 M

3 0
3 years ago
Read 2 more answers
The men's world record for swimming 1500 m in a long course pool is 14 min 34.56 s. At this rate how many seconds would it take
vlabodo [156]
Distance = 1500m, time = 14min 34.56s = 14*60 + 34.56 = 874.56s

Speed = Distance / time = 1500/874.56 = 1.715 m/s

In order to swim 0.7 miles, 1 mile = 1609.344 m

Time = Distance / speed = 1609.344 m / 1.715 m/s = 938.393 seconds

938/60 = 15 minutes, 38 seconds.

= 15 minutes 38.393 seconds.
6 0
3 years ago
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