The ball spins once around the circle in 0.20 s, meaning it travels a distance equal to its circumference in that time, giving it a linear speed of
<em>v</em> = (2<em>π</em> (0.5 m)) / (0.20 s) = 5<em>π</em> m/s ≈ 15.708 m/s
Use this compute the magnitude of the centripetal acceleration <em>a</em> :
<em>a</em> = <em>v</em>²/ (0.5 m) = 50<em>π</em>² m/s² ≈ 493.48 m/s²
Use Newton's second law to compute the mangitude of the tension <em>F</em> in the string:
<em>F</em> = (0.05 kg) <em>a</em> = 5/2 <em>π</em>² N ≈ 24.674 N ≈ 25 N
The internal energy of an ideal gas is given by:
where
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
k=3 for monoatomic gases, k=5 for diatomic gases
In this problem, we have n=3.0 mol of a diatomic gas (k=5) at T=288 K. Substituting these numbers into the equation, we find the internal energy of the gas:
<h2><em>how far will a freely falling object fall from rest in 5 seconds?</em></h2>
- <em>If an object free falls from rest for 5 seconds, its speed will be <u>about 50 m/s.</u></em>
<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>
<em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> learning</u></em>