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Lisa [10]
3 years ago
5

Which process takes place when large rocks crumble due to oxidation?

Chemistry
2 answers:
Natalija [7]3 years ago
7 0

Answer:

c) physical weathering

Hope this helps in the future <3

Zielflug [23.3K]3 years ago
4 0

D) chemical weathering​

Explanation:

When large rocks crumble due to oxidation, chemical weathering has taken place.

  • Weathering is an essential process on the earth. It is driven strictly by the external heat engine.
  • Weathering is defined as the physical disintegration and chemical decomposition of rocks to form sediments and soils.
  • When rocks decompose chemically, their structure weakens because they undergo chemical reactions.
  • During oxidation, oxygen combines with rock materials to form new products. This one process of chemical weathering.
  • Other examples are hydrolysis, carbonation, hydration e.t.c

Learn more:

Contact metamorphism brainly.com/question/1970623

#learnwithBrainly

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How many moles of co2 are found in a 168.2 gram sample
andrew11 [14]

Answer:

Number of moles = 3.82 mol

Explanation:

Given data:

Number of moles of CO₂ = ?

Mass of CO₂ = 168.2 g

Solution:

Number of moles = mass/molar mass

Molar mass of CO₂ = 44 g/mol

By putting values,

Number of moles = 168.2 g/ 44 g/mol

Number of moles = 3.82 mol

6 0
3 years ago
Two proteins interact to form a multimeric complex. When one of the proteins is mutated, there is a substantial loss of function
ololo11 [35]

Answer:

<h2>4. dominant negative</h2>

Explanation:

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3 years ago
The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

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Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
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9966 [12]
It should be KNO3 to the best of my understanding
7 0
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Read 2 more answers
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Ostrovityanka [42]

Answer: it should be 2.8

Explanation:

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