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Dominik [7]
3 years ago
5

Anne’s marginal income tax rate is 32 percent. She purchases a corporate bond for $10,000 and the maturity, or face value, of th

e bond is $10,000. If the bond pays 5 percent per year before taxes, what is Anne’s annual after-tax rate of return from the bond if the bond matures in 1 year? What is her annual after-tax rate of return if the bond matures in 10 years?
Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

Anne’s after-tax rate of return from the corporate bond is 3.5% or 5% x (1-.3). Because interest from the bond is taxed annually and her rate is assumed to be constant, the after-tax rate of return doesn’t depend on her investment horizon. Thus, her annual after-tax rate of return remains at 3.5% if the bond matures in ten years.

Step-by-step explanation:

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Sound travels about 335 meters/second. How many kilometers would a sound travel in 1 minute?
Lelechka [254]
If sounds travel 335 meters in 1 second , in 1 minute it travels 60 times that distance :

335m × 60 = 20100 meters
Sounds travel 20100 meters per minute
if 1000 meters = 1 km ,
20100 meters = 20100/1000 km
20100 meters = 20.1 Km

Awnser : Sound would travel 20.1 km in one minute
7 0
3 years ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
What’s the answer for this?
Yuliya22 [10]

Answer:

1.98

Step-by-step explanation:

sin(26) = EF/4.5 -->

.44 = EF/4.5 -->

.44 * 4.5 = EF -->

1.98 = EF

5 0
3 years ago
If there are 205 students in the school, which is the best estimate of the number of students that are in the 5th grade?
Mila [183]

Answer:

34 people

Step-by-step explanation:

8 0
3 years ago
Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.
Tanzania [10]

Answer:

z= 3.63

z for  significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42     against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z  test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for  significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis  and accept the alternative hypothesis that more than 42%  people owned cats.

4 0
3 years ago
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