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DedPeter [7]
3 years ago
13

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity re

mains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting? (Assume that up is the positive direction.) a. +2.93 times 10^5 J b. 0J c. Answer is not obtainable, because insufficient information about the skydiver's speed is given. d. -2.93 times 10^5 J
Physics
1 answer:
natka813 [3]3 years ago
5 0

Answer: Workdone293.02KJ

Explanation: The equation to use to calculate Workdone = Change in KE + Change in PE

Assuming velocity is constant,KE becomes 0

Workdone= Change in PE=mg

W=92×9.8×325=293.02KJ

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2 years ago
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What is the concentration of H^ + at apH = 2 ? Mol / L What is the concentration of H^ + ions at apH = 6 ? Mol/L How many more H
Nonamiya [84]

Answer:

The concentration of hydrogen ion at pH is equal to 2 := [H^+]=0.01 mol/L

The concentration of hydrogen ion at pH is equal to 6 : [H^+]'=0.000001 mol/L

There are 0.009999 more moles of  H^+ ions in a solution at a pH = 2 than in a solution at a pH = 6.

Explanation:

The pH of the solution is the negative logarithm of hydrogen ion concentration in an aqueous solution.

pH=-\log [H^+]

The hydrogen ion concentration at pH is equal to 2 = [H^+]

2=-\log [H^+]\\

[H^+]=10^{-2}M= 0.01 M=0.01 mol/L

The hydrogen ion concentration at pH is equal to 6 = [H^+]

6=-\log [H^+]\\\\

[H^+]=10^{-6}M= 0.000001 M= 0.000001 mol/L

Concentration of hydrogen ion at pH is equal to 2 =[H^+]=0.01 mol/L

Concentration of hydrogen ion at pH is equal to 6 = [H^+]'=0.000001 mol/L

The difference between hydrogen ion concentration at pH 2 and pH 6 :

= [H^+]-[H^+]' = 0.01 mol/L- 0.000001 mol/L = 0.009999 mol/L

Moles of hydrogen ion in 0.009999 mol/L solution :

=0.009999 mol/L\times 1 L=0.009999 mol

There are 0.009999 more moles of  H^+ ions in a solution at a pH = 2 than in a solution at a pH = 6.

8 0
3 years ago
The following three questions refer to a situation in which a driver is in a car that crashes into a solid wall. The car comes t
Andreas93 [3]

Answer:

1) p₀ = 45000 N / s ,   p₀ '= 1800 , b)  I = -45000 N s ,  I = 1800 Ns

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Impulse equals the change in momentum

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1) the initial moment of the car

         p₀ = M v

          p₀ = 1500 30

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the change at the moment is

          Δp = 45000

because the end the car is stopped

moment of the person

          P₀ ’= m v

         p₀ '= 60 30

          p₀ '= 1800

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        person

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a) This area is the one that absorbs most of the vehicle impulse

be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease

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Copper penny is the answer

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It is basically 3 types.

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