The equilibrium conditions allow to find the results for the balance forces are:
When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.
∑ F = 0
∑ τ = 0
Where F are the forces and τ the torques.
The torque is the product of the force and the perpendicular distance to the point of support,
The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.
We write the translational equilibrium condition.
F₁ - W₁ - W₂ + F₂ = 0
We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.
F₂ 2 - W₁ 1 - W₂ 1.5 = 0
Let's calculate F₂
F₂ = 
F₂ = (m g + M g 1.5)/ 2
F₂ = 
F₂ = 558.6 N
We substitute in the translational equilibrium equation.
F₁ = W₁ + W₂ - F₂
F₁ = (m + M) g - F₂
F₁ = (12 +68) 9.8 - 558.6
F₁ = 225.4 N
In conclusion using the equilibrium conditions we can find the forces of the balance are:
Learn more here: brainly.com/question/12830892
The mass of the water in the system is one parameter that can be taken into consideration that is kept constant.
Describe a constant.
A constant in science is a kind of unaltered variable that stays constant together with the experimental process.
It is important to take into account a system's constants, which cannot be altered by experiments or observations.
In conclusion, the mass of the water can be taken into consideration as a continuous system parameter.
Learn more about the constant of the system here:
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Answer : The specific heat of unknown sample is, 
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-[q_2+q_3]](https://tex.z-dn.net/?f=q_1%3D-%5Bq_2%2Bq_3%5D)
![m_1\times c_1\times (T_f-T_1)=-[m_2\times c_2\times (T_f-T_2)+m_3\times c_3\times (T_f-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29%2Bm_3%5Ctimes%20c_3%5Ctimes%20%28T_f-T_2%29%5D)
where,
= specific heat of unknown sample = ?
= specific heat of water = 
= specific heat of copper = 
= mass of unknown sample = 72.0 g = 0.072 kg
= mass of water = 203 g = 0.203 kg
= mass of copper = 187 g = 0.187 kg
= final temperature of calorimeter = 
= initial temperature of unknown sample = 
= initial temperature of water and copper = 
Now put all the given values in the above formula, we get
![0.072kg\times c_1\times (39.4-80.0)^oC=-[(0.203kg\times 4186J/kg^oC\times (39.4-11.0)^oC)+(0.187kg\times 390J/kg^oC\times (39.4-11.0)^oC)]](https://tex.z-dn.net/?f=0.072kg%5Ctimes%20c_1%5Ctimes%20%2839.4-80.0%29%5EoC%3D-%5B%280.203kg%5Ctimes%204186J%2Fkg%5EoC%5Ctimes%20%2839.4-11.0%29%5EoC%29%2B%280.187kg%5Ctimes%20390J%2Fkg%5EoC%5Ctimes%20%2839.4-11.0%29%5EoC%29%5D)
Therefore, the specific heat of unknown sample is,
Answer:
(c) always equal to the weight of the liquid displaced.
Explanation:
Archimedes principle (also called physical law of buoyancy) states that when an object is completely or partially immersed in a fluid (liquid, e.t.c), it experiences an upthrust (or buoyant force) whose magnitude is equal to the weight of the fluid displaced by that object.
Therefore, from this principle the best option is C - always equal to the weight of the liquid displaced.
