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alisha [4.7K]
3 years ago
8

A local AM radio station broadcasts at a frequency of 696 KHz. Calculate the energy of the frequency at which it is broadcasting

.
Physics
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

E=4.61\times 10^{-28}\ J

Explanation:

Given that,

The frequency of local AM radio station, f = 696 KHz = 696000 Hz

We need to find the energy of the frequency at which it is broadcasting.

We know that,

Energy of a wave, E = hf

Where

h is Planck's constant

Put all the values,

E=6.63\times 10^{-34}\times 696000\\\\=4.61\times 10^{-28}\ J

So, the energy of the wave is equal to4.61\times 10^{-28}\ J.

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A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
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<u>Answer:</u>

The height of ramp = 124.694 m

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Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

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substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

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Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

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A resistor, inductor, and a battery are arranged in a circuit. The circuit has an inductance of L = 1 H and a resistance of 1.4
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Answer:

\tau \approx 7.14 \times 10^{-4}s \approx0.714ms

Explanation:

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