Answer:
T1 = 130N, T2 = 370N
Explanation:
In order for the system to be at rest, the sum of all forces must be zero and the torque around a point on the beam must be zero.
1. forces:
Let tension in rope 1 be T1 and in rope 2 be T2:
ma = T1 + T2 - 100N - 400N = 0
(1) T1 + T2 = 500N
2. torque around the center point of the beam:
τ = r x F = 5*T1 + 3*400N - 5*T2 = 0
(2) T1 - T2 = -240N
Solving both equations:
T1 = 130N
T2 = 370N
The runner has initial velocity vector
and acceleration vector
so that her velocity at time is
She runs directly east when the vertical component of is 0:
It's not clear what you're supposed to find at this particular time... possibly her position vector? In that case, assuming she starts at the origin, her position at time would be
so that after 10.4 s, her position would be
which is 19.9 m away from her starting position.
#1
As per work energy theorem work done by all forces must be equal to change in its kinetic energy
so correct answer will be
= change in kinetic energy
#2
Torque is defined as
so here torque will be maximum when applied force is perpendicular to the rod
so first figure of rod is correct for maximum torque
#3
When car makes turn then its passengers moves outwards which is due to the property of inertia because due to this property passengers has tendency to move in same direction and hence it feels to move outwards
So correct answer will be
<em>inertia</em>
#4
As per energy conservation we can say
initial potential energy = final kinetic energy