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Talja [164]
3 years ago
14

Which of the following statements concerning the attraction of ions to polar molecules is/are CORRECT? 1. The force of attractio

n between an ion and a polar molecule is inversely proportional to the square of the distance between the center of the ion and the oppositely charged pole of the dipole. 2. The higher the ion charge, the stronger the attraction between the ion and a polar molecule. 3. The greater the magnitude of the dipole, the greater the attraction between the ion and a polar molecule.
Chemistry
1 answer:
Kitty [74]3 years ago
6 0

Answer:

1, 2 and 3 are correct.

Explanation:

The force of the attraction is calculated by Coulomb's law as:

\frac {K\times q_1\times q_2}{d^2}

Where,  

K is the Coulomb's constant having value 9×10⁹ N. m²/C²

q_1\ and\ q_2 are the charges on the dipole and ion respectively.

d is the distance between them.

Since F is inversely proportional to square of distance between them, so statement 1 is true.

F is directly proportional to the charge , so on increasing charge, force of attraction increases. Hence, statement 2 is true.

The greater the magnitude of the dipole means the greater the charge on dipole. Hence, statement 3 is also true.

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A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of
Bad White [126]

Answer:

a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}

The number of moles of the ideal gas is:

n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}

n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}

n = 5.541\,mol

The final temperature is:

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}

T_{2} = 360.955\,K

The final pressure is:

P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}

P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)

P_{2} = 138569.171\,Pa\,(1.386\,bar)

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}

T_{2} =  347.348\,K

The final volume is:

V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

V_{2} = 0.14\,m^{3}

4 0
3 years ago
A horse gallops along a racecourse at a speed of 40 km/h. It takes the horse 3 minutes to run the length of the track.
Natali [406]

To convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

<h3>How to convert minutes into hour?</h3>

We know that in hour, there are 60 minutes so if we go from minutes to hours then we have to divide the number by 60 and when we go from hours to minutes we multiply with the same 60 number.

So we can conclude that to convert minutes to hours we divide the minutes by 60. So if we divide 3 by 60 we get 0.05 hours.

Learn more about hour here: brainly.com/question/291457

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7 0
2 years ago
When an acid is added to a base, which if the following changes in pH might be observed?
Licemer1 [7]
Im just guessing, so i think is A
5 0
2 years ago
Potential energy due to the position of an object above earth surface is called
KengaRu [80]

ANSWER:

Potential energy due to the position of an object above Earth&#39;s surface is called gravitational  potential energy.

EXPLANATION:

Gravitational energy is the potential energy compared with gravitational force, as work is  needed to further things against Earth’s gravity. The potential energy due to high positions is  called gravitational potential energy, and is evidenced by water in an elevated storage or kept  behind a dam. If an article falls from one point to different point inside a gravitational field, the  force of gravitation will do actual work on the object, and the gravitational potential energy will  decrease by the same amount.

7 0
3 years ago
Given the balanced equation representing a reaction: 2na(s) + cl2(g) → 2nacl(s) + energy if 46 grams of na and 71 grams of cl2 r
igor_vitrenko [27]
Answer is: 2) 117g.
2Na + Cl₂ → 2NaCl
Step 1: calculate amount of substance of sodium and chlorine.
n(Na) = m(Na)÷M(Na) = 46g ÷ 23 g/mol = 2 mol.
n(Cl₂) = m(Cl₂)÷M(Cl₂) = 71g ÷ 71 g/mol = 1 mol.
Step 2: calculate amount of substance and mass of sodium-chloride.
Because both sodium and chlorine react completely, we can use both n to compare with n of NaCl.
n(Na) : n(NaCl) = 2:2, 2 mol : n(NaCl) = 2:2
n(NaCl) = 2mol, m(NaCl) = 2mol ·5805 g/mol = 117 g.

6 0
3 years ago
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