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Zanzabum
3 years ago
6

A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by

a distance of 10.0 cm. What is the angular magnification? (Assume the near point is 25.0 cm.)
Physics
1 answer:
Marizza181 [45]3 years ago
6 0

Answer:

-252.52

Explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

f_o = Focal length of objective = 0.9 cm

f_e = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

m=-\frac{L}{f_o}\frac{D}{f_e}\\\Rightarrow m=-\frac{10}{0.9}\times \frac{25}{1.1}\\\Rightarrow m=-252.52

The angular magnification of the compound microscope is -252.52

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Answer:

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Explanation:

We have,

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Plugging all values, we get :

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