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AURORKA [14]
3 years ago
15

The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were obser

ved by Tycho Brahe and analyzed by Johannes Kepler. A good starting point for understanding this (as well as the speed of the space shuttle and the height of geostationary satellites) is the simplest orbit - a circular one. This problem concerns the properties of circular orbits for a satellite orbiting a planet of mass M. Use G for the universal gravitational constant. Find the orbital period T.
Physics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

Explanation:

We know that , for an object to remain in  circular motion , a force towards centre is required which is called centripetal force. In the circular motion of

satellites around planet , this force is provided by the gravitational attraction between satellite and planet.

If M be the mass of planet and m be the mass of satellite,  G be gravitational constant and R be the distance between planet and satellite or R be the radius of orbit

Gravitational force = G Mm / R²

If v be the velocity with which satellite is orbiting

centripetal force

= m v² /R

Centripetal force = gravitational attraction

m v² /R  =  G Mm / R²

v = \sqrt{\frac{GM}{R} }

Time period = time the satellite takes to make one rotation

= distance / orbital velocity

= 2πR/ v

= \frac{2\pi R\sqrt{R} }{\sqrt{GM} }

T = \frac{2\pi R^\frac{3}{2} }{\sqrt{GM} }

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Answer:

51kg

Explanation:

w=FxS

2500=Fx5

F=2500/5=500

mass = 500/9.8 = 51kg

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2 years ago
The body weighing 2 kg moves through the horizontal surface and crosses the path x = 75 cm The coefficient of friction of the bo
Taya2010 [7]

The kinetic energy of the body in definitive position is 4.24 J.

Explanation:

As per the work energy theorem, the work done on any system or object to move it from one position to another is equal to the change in kinetic energy of the object. In this case, the body weighing 2 kg is moved over an horizontal surface for a distance of 75 cm. As there will be frictional force acting on the body while moving over the surface. This frictional force multiplied by the distance the object is moved will give the work done on the body.

Frictional force = Coeffficent of friction × Normal force.

As the weight of the body is 2 kg, the normal force acting on it will be mass multiplied with acceleration due to gravity.

Frictional force = - 0.8×9.8 × 2 =-15.68 N

So the work done will be the product of frictional force with the displacement of 75 cm or 0.75 m.

Work done =  Frictional force × Displacement

Work done = -15.68×0.75 = -11.76 J.

So the work is done by the object.

If the kinetic energy of the body at starting is 16 J, then the kinetic energy of the body at definitive position will be obtained as below.

Work done = change in kinetic energy

-11.76 J = Final kinetic energy-16 J

Final Kinetic energy = - 11.76+16

Final kinetic energy = 4.24 J

Thus, the kinetic energy of the body in definitive position is 4.24 J.

3 0
3 years ago
A compass taken to Earth's moon does not point in a specific direction on the moon.
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C) the moon does not have a strong magnetic field
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3 years ago
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Which statement correctly describes the electrons in a water molecule?. . A.Which statement correctly describes the electrons in
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The statement “Electrons are pulled closer to the oxygen atom” correctly describes the electrons in a water molecule. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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3 years ago
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A 65.0-Ω resistor is connected to the terminals of a battery whose emf is 12.0 V and whose internal resistance is 0.5 Ω. Calcula
Luda [366]

Answer:

a) 0.1832 A

b) 11.91 Volts

c) 2.18 Watt , 0.0168 Watt

Explanation:

(a)

R = external resistor connected to the terminals of the battery = 65 Ω

E = Emf of the battery = 12.0 Volts

r = internal resistance of the battery = 0.5 Ω

i = current flowing in the circuit

Using ohm's law

E = i (R + r)

12 = i (65 + 0.5)

i = 0.1832 A

(b)

Terminal voltage is given as

V_{ab} = i R

V_{ab} = (0.1832) (65)

V_{ab} = 11.91 Volts

(c)

Power dissipated in the resister R is given as

P_{R} = i²R

P_{R} = (0.1832)²(65)

P_{R} = 2.18 Watt

Power dissipated in the internal resistance is given as

P_{r} = i²r

P_{r} = (0.1832)²(0.5)

P_{r} = 0.0168 Watt

5 0
3 years ago
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