A 2 kg bowlling ball is 2.5 meters off the ground on a post when it falls just before it reachers the ground it is traveling m/s
1 answer:
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Answer : The concentration after 17.0 minutes will be,
Explanation :
The expression for first order reaction is:
where,
= concentration at time 't' (final) = ?
= concentration at time '0' (initial) = 0.100 M
k = rate constant =
t = time = 17.0 min = 1020 s (1 min = 60 s)
Now put all the given values in the above expression, we get:
Thus, the concentration after 17.0 minutes will be,