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3 years ago

12

Saline solutions (nacl in water) used to deliver intravenous drugs are 0.89%(w/v). what mass of nacl is found in 200 ml of such

a solution?

1 answer:

Gnom [1K]3 years ago

6 0

A ratio of 0.89% w / v or 0.0089 in fraction means that there is 0.89 weight of NaCl pero volume of solution. Therefore the mass of NaCl is:

mass NaCl = 0.0089 * 200

<span>mass NaCl = 1.78 grams</span>

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zheka24 [161]

Are you referring to DNA?

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3 years ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

50

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

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3 years ago

B. Organic sedimentary rock

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Answer:

A. Clastic sedimentary rocks

Explanation:

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Hope this helps! :)

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3 years ago

A sample of gas has a volume of 3.00 liters at a temperature of 30.℃. At what temperature would the volume be 1.50 liters?

erastovalidia [21]

The answer I got is 151. 5 K. I hope that helps.

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3 years ago

Determine the bond type formed between Hg and F

charle [14.2K]

Answer:

Multivalent Ionic

Explanation:

The type of bond formed between the atoms of two elements can easily be deduced from the magnitude of electronegativity difference between the two bonding atoms.

A summary of electronegativity differences and corresponding types of bonds are shown below as adapted from chemlibretexts, where Δχ is the difference in electronegativity ;

ionic if Δχ ≥ 2.0

polar if 2.0 > Δχ > 0.5

nonpolar if 0.5 > Δχ

To determine the type of bond between Hg and F. Hg has an electronegativity of 2 while F has an electronegativity of 4. the difference in electronegativity (Δχ) is 4 - 2 = 2

This corresponds to a multivalent ionic bond because mercurous ion is the

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3 years ago