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Natali [406]
3 years ago
10

What is the electron configuration of Ba

Chemistry
1 answer:
Marizza181 [45]3 years ago
4 0
(Xe) 6s2 is the ec of ba
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What is the maximum number of electrons that can occupy an orbital labeled dxy?
Rina8888 [55]
2 is the maximum number of electrons that can occupy an orbital labeled dyx
Hope this help :)
6 0
3 years ago
An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at
pochemuha

Total internal energy change is equals to -44.83kJ

Q=-73.2kJ (negative sign indicates that heat was released by the system),

P= 50.0atm

ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)

ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre

work done by the system (w)= -PΔV

w= -(50.0×(-5.60)) atm×litre=  280atm litre

1 atm litre= 101.325J

w= 280 ×101.325 J= 28,371J

1kJ=1000J,

w=28.37KJ,

so putting in the values in equation (1)...

energy change(ΔU) = -73.2 kJ + 28.37 kJ

= - 44.83 kJ

7 0
3 years ago
3. (a) The nitrogen oxide (NO) molecule has a bond length of 140 pm. Calculate the dipole moment, in Debyes, that results if the
SSSSS [86.1K]

Answer:

The calculations is shown in the attached file.

Explanation:

  • The concept of dipole moment is applied here. the size of the dipole moment is given by multiplying the size of the charge by the distance apart.
  • For simpler molecules, the sizes of the dipole moments are approximately proportional to the difference between the electronegativities of the atoms. Dipole moments are usually measured in debyes (D).

Dipole moments (μ) = q x r

The detailed calculation is shown in the attachment.

7 0
3 years ago
What is one observation you can make aboit venus​
PilotLPTM [1.2K]

Answer:

The temperature is very hot.

Explanation:

The gas around the planet traps the suns heat and makes it the hottest planet in our solar system.

8 0
3 years ago
The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
motikmotik

Answer: 1.466 g/mL

Explanation:

\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot  \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}

6 0
2 years ago
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