2 is the maximum number of electrons that can occupy an orbital labeled dyx
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Total internal energy change is equals to -44.83kJ
Q=-73.2kJ (negative sign indicates that heat was released by the system),
P= 50.0atm
ΔU= Q + W, FIRST LAW OF THERMODYNAMICS..........(1)
ΔV= Final volume - initial volume= 2.00 litre - 7.60litre= -5.60litre
work done by the system (w)= -PΔV
w= -(50.0×(-5.60)) atm×litre= 280atm litre
1 atm litre= 101.325J
w= 280 ×101.325 J= 28,371J
1kJ=1000J,
w=28.37KJ,
so putting in the values in equation (1)...
energy change(ΔU) = -73.2 kJ + 28.37 kJ
= - 44.83 kJ
Answer:
The calculations is shown in the attached file.
Explanation:
- The concept of dipole moment is applied here. the size of the dipole moment is given by multiplying the size of the charge by the distance apart.
- For simpler molecules, the sizes of the dipole moments are approximately proportional to the difference between the electronegativities of the atoms. Dipole moments are usually measured in debyes (D).
Dipole moments (μ) = q x r
The detailed calculation is shown in the attachment.
Answer:
The temperature is very hot.
Explanation:
The gas around the planet traps the suns heat and makes it the hottest planet in our solar system.