You are asking for the condition needed for the
<span>two segments to be perpendicular to each other. </span>
<span>If the slope of one segment is m, then the slope of a perpendicular segment would be -1/m </span>
<span>this means that m2 = -1/m and so m2 x m = -1 </span>
<span>If you look carefully at your choices, the 3rd answer involves the two slope and has the -1. It's </span>
<span>the correct answer.</span>
Answer:
2/5 or .4
Step-by-step explanation:
basically look at the points where the line meets the graph. two points would be 0,20 and 50,40. then count the amount that it changes vertically and then horizontally. +20vertical +50 horizonal giving the slope 20/50. this can then be simplified to 2/5 or the equivalent number .4
Furthest from 0, so I am going to take the absolute value of these numbers. The absolute value will tell us how far away from 0 these numbers are.
|-1/2| = |- 0.5| = 0.5
|8/9| = |0.88| = 0.88
|0.2| = 0.2
so the number furthest from 0 is 8/9
Answer:
a₃₅ = 182
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 17 - 12 = 22 - 17 = 5
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 12 and d = 5 , then
a₃₅ = 12 + (34 × 5) = 12 + 170 = 182
40√3+432/7 is the answer
Hope this helps :D