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vladimir1956 [14]
3 years ago
8

A solid sphere of uniform density starts from rest and rolls without slipping down an inclined plane with angle θ = 30o. The sph

ere has mass M = 8 kg and radius R = 0.19 m . The coefficient of static friction between the sphere and the plane is μ = 0.64. What is the magnitude of the frictional force on the sphere?
I got 21.168N and the computer told me I was wrong because I was trying to find force of the max static instead of the actual static force. Please help!
Physics
1 answer:
kondaur [170]3 years ago
8 0
M*g*sin20-f=m*a 
<span>and the rotational frame </span>
<span>f*r=I*a/r </span>
<span>where f is the force of friction, a is the translational acceleration and I is the moment of inertia of the sphere </span>

<span>combine and solve for f </span>
<span>a=g*sin20-f/m </span>
<span>and </span>
<span>f*r^2/I=g*sin20-f/m </span>
<span>or </span>
<span>f=g*sin20/(r^2/I+1/m) </span>

<span>I=2*m*r^2/5 </span>
<span>therefore </span>
<span>f=2*m*g*sin20/7</span>
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